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Two sides to every coin
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∙ 15y ago
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What r the dimensions of mutual inductance?
Obviously there is more than one way to do this. VL = Ldi/dt Volts has units of Joules/Coulomb: J/C i has units of Coulombs/second: C/s So di/di is C/s^2 L has units of J/C / C/s^2 = Js^2/C^2 Ic = CdV/dt => Ic/dV/dt = C/s / J/C-s = C/s * C-s/J = C^2/J C has units of C^2/J OR you could just type Q = CV => C = Q/V = C/J/C = C^2/J same answer R = V/I => J/C / C/s = J-s/C^2
2 s to every s?
2 Sides to every story
What is 2 s to every s mean?
Two sides to every story.
What is the area formula for an triangle?
It is sqrt{s*(s-a)*(s-b)*(s-c)} where the lengths of the three sides are a, b and c units and s = (a+b+c)/2.
2 S to E S?
2 Sides to Every Story
2 S on a c?
2 sides on a coin.
What is the area of a 2 by 8 by 8 and a half cm triangle?
Assuming 2, 8, and 8.5 are the lengths of the sides, the area is 7.929 cm^2. Using Heron's formula, A = sqrt(s * (s-a) * (s-b) * (s-c)) where a, b, and c are the lengths of the sides and s = (a + b + c)/2
Area of scalene triangle?
The answer depends on what information you do have.Suppose you know only the lengths of the sides (a, b and c), then let s = (a + b + c)/2.Then area = sqrt[s*(s - a)*(s - b)*(s - c)]If 2 sides and the included angle, then area = 1/2*a*b*sin(C).There are other formulae.
How is the area of a triangle affected if the height is doubled but the length of the base remains the same?
The area is doubled. a,b - cathetus; c - hypotenuse; h - height; S - area. S = (a*b)/2 = (c*h)/2 obviously if k is the doubled height. and A is the new area. A = (c*k)/2 = (c*2h)/2 = c*h and A = S*2
2 equals S of a C?
2 Sides of a Coin
2 S T E C?
?What?
What is the surface area triangular prism?
If the sides of the triangular base are a, b and c and the height is h, the area is 2sh + 2 sqrt (s(s-a)(s-b)(s-c)) where s = (a +b +c)/2 [I. e. s is the semiperimeter of the base] and sqrt means"the square root of "
