And what is the question?If you want to factor that, first take out the common factor of 2, and put whatever remains in parentheses. Then you can use the rule to factor the difference of two squares, to factor what remains within parentheses.
The answer to x2 - 2x - 4y2 - 4y =(x - 2y)(x - 2y - 2)
2
(x + 2)(x - 9)
(x + 2)(x - 4)
(x + 2)(x - 2)
x = ? 42 = x squared minus x
No
x(x - 2)
-3
(x - 2)(x^2 + x + 3)
x-8
x^2 - y^2 - 4 is in its simplest form.