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If you are wanting factors there is:
1, 3, 13, 39
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∙ 12y ago
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Is 39 divisible by 2?
No, it is divisible by 1, 3, 13, 39.
What is the number nearest to 39 that is exactly by divisible 4?
40 is nearest to 39 and is exactly by divisible 4
Is 39 divisible by 6?
No. 39 is odd but 6 is even and all multiples of 6 are even.
Is 39 divisible by 5?
yes if you include decimal places.... any number is divisible except zero. The answer is 7.8
Is 39 divisible by3?
39 is divisible by 3. It equals 13. You can tell if a number is divisible by 3 by adding up the digits in the number and see if it is divisible by three. Here's and example: 197 1+9+7= 17 and 17 isn't divisible by three. 576 5+7+6= 18 and 3 goes into 18 6 times so it is divisible by 3
Is 39 divisible by 2?
No, it is divisible by 1, 3, 13, 39.
What is the number nearest to 39 that is exactly by divisible 4?
40 is nearest to 39 and is exactly by divisible 4
Is 39 divisible by 4?
No - 39/4 = 9.75
Why is 39 a composite number?
Because it is divisible by numbers other than 1 and itself. 39 is divisible by 1, 3, 13, 39.
Is 39 divisible 2?
No.
Is 39 divisible by 3?
Yes; if 39 is divided by 3, you get 13. Another way to check this is add 13+ 13+ 13, and you will get 39.
What number is between 21 and 39 that is divisible by 2 and 5?
If its divisible by 5 AND 2 it must be divisible by 10 So you just have to pick the only number between 21 and 39 that's divisible by 10
What numbers are divisible by 39?
All multiples of 39, which is an infinite number.
What numbers is 39 divisible by?
3,2,5,6,9,10
Is 39 divisible by 10?
39 divided by 10 is 3.9 so 39 goes into 10 3times
Can you divide 100 by 39?
Certainly I can: 100 ÷ 39 = 222/39 ≈ 2.564 However, 100 is not divisible by 39, that is 39 does not divide into 100 with no remainder.
Is 39 a prime or composite Explain how you know?
composite 3 goes into 3 or 30 3 goes into 9 so 3 goes into 39 13 + 13 + 13 = 39 = 3 x 13 ------------------------------------- Applying a divisibility test: To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3. As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3. For 39 this gives: 39 → 3 + 9 = 12 12 → 1 + 2 = 3 3 is one of {3, 6,9} so 39 is divisible by 3. As 39 is divisible by 3 (that is 3 is a factor of 39 that is less than 39) and 3 is greater than 1 then 39 is a composite number.
