3 x -3 + 1 = (-9) + 1 = -8.
x3 - 3x2 + x - 3 = (x2 +1)( x - 3)
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
x3 - 3x2 + x - 3 = (x - 3)(x2 + 1)
(X + 1)3 = X3 + 3X2 + 3X + 1
Dividend: 4x4-x3+17x2+11x+4 Divisor: 4x+3 Quotient: x3-x2+5x-1 Remainder: 7
The quotient is: x^2 +2x +3
The integral of 1 + x2 is x + 1/3 x3 + C.
lim (x3 + x2 + 3x + 3) / (x4 + x3 + 2x + 2)x > -1From the cave of the ancient stone tablets, we cleared away several feet of cobwebs and unearthed"l'Hospital's" rule: If substitution of the limit results in ( 0/0 ), then the limit is equal to the(limit of the derivative of the numerator) divided by (limit of the derivative of the denominator).(3x2 + 2x + 3) / (4x3 + 3x2 + 2) evaluated at (x = -1) is:(3 - 2 + 3) / (-4 + 3 + 2) = 4 / 1 = 1
x3 + x2 - 17x + 15 = (x - 1)(x - 3)(x + 5). Thus, the zeros are 1, 3, and -5. All three zeros are rational.
The answer to x4+x3-14x2+4x+6 divided by x-3 is x3+4x2-2x-2
∫ (x2+3) = ∫x2 + ∫3(1/3)X3 + 3X + C
x3 + x2 - 3x - 3 x(x2 + x - 3) - 3