∫ (x2+3) = ∫x2 + ∫3
(1/3)X3 + 3X + C
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sqrt(1) + 3*sqrt(x) = 1 + 3*x^1/2So the antiderivative is x + [3*x^(3/2)]/(3/2) + c = x + 2*x^(3/2) + c where c is the constant of integration.
(x + 3)(x + 3)
x + 5
Asuming it starts "x squared" the the answer is (x-3)(x-3) or (x - 3)squared
(x + 3)(x + 2)