4 quavers in a minim (music).
It is: 4*(q+p)
-q-11=2q+4 you would subtract 4 from both sides 4 and -4 cancel out and -11-4= -15 then you get -q-15=2q then you would add Q(1) to both sides (-q and q cancel out) then u get -15=3q thn u divide 3 to both sides (3 and 3 become q) then u get q=-5
Minutes, Quarter, Basketball.
To solve an equation, the goal is to get the variable by itself. In this case the variable is q. -6=8q-4 first you want to get 8q by itself because the 8 and the q are together right now. So add 4 to each side to cancel it out on the side that has a -4. -6+4=8q simplify. -2=8q then to get rid of the 8, you have to divide both sides by 8 and then you get q by itself. -2/8=q simplify again. -1/4=q q=-1/4 :)
When: p=12 and q=3 Then when: p=76 and so q=19 Because: 12/3=4 and 76/19=4
4 musicians in a quartet
To solve for this, you need to isolate "m." To accomplish this, subtract 4m from both sides of the equation. This should change the equation to q - 4z = 4m. Then you divide both sides by 4, getting q/4 - 4z/4 = m. After completing the division, you should get 1/4q - z = m.
4 S in a Q
I'm on it . . .p = 2 / (m + q)Multiply each side by (m + q) :p (m + q) = 2Divide each side by 'p' :m + q = 2/pSubtract 'm' from each side:q = 2/p - m
'q' and 1/(4 pi ε0)
A. Q. M. Bazlul Karim was born in 1920.
That's not a question. Q = (m)(c)(deltaT)
I think so.Sum = m + q
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According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 1 words with the pattern Q--M-Q-M. That is, eight letter words with 1st letter Q and 4th letter M and 6th letter Q and 8th letter M. In alphabetical order, they are: qaimaqam
If M P and Q are collinear and MP plus PQ equals MQ then P is between M and Q.
Depends if your name begins with 'A to M' or 'M to Q'. 'A to M' = Run 'M to Q' = Ran Hope this helps! :D