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4 quavers in a minim (music).

Q: 4 q in a m

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It is: 4*(q+p)

-q-11=2q+4 you would subtract 4 from both sides 4 and -4 cancel out and -11-4= -15 then you get -q-15=2q then you would add Q(1) to both sides (-q and q cancel out) then u get -15=3q thn u divide 3 to both sides (3 and 3 become q) then u get q=-5

Minutes, Quarter, Basketball.

To solve an equation, the goal is to get the variable by itself. In this case the variable is q. -6=8q-4 first you want to get 8q by itself because the 8 and the q are together right now. So add 4 to each side to cancel it out on the side that has a -4. -6+4=8q simplify. -2=8q then to get rid of the 8, you have to divide both sides by 8 and then you get q by itself. -2/8=q simplify again. -1/4=q q=-1/4 :)

When: p=12 and q=3 Then when: p=76 and so q=19 Because: 12/3=4 and 76/19=4

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4 musicians in a quartet

To solve for this, you need to isolate "m." To accomplish this, subtract 4m from both sides of the equation. This should change the equation to q - 4z = 4m. Then you divide both sides by 4, getting q/4 - 4z/4 = m. After completing the division, you should get 1/4q - z = m.

4 S in a Q

I'm on it . . .p = 2 / (m + q)Multiply each side by (m + q) :p (m + q) = 2Divide each side by 'p' :m + q = 2/pSubtract 'm' from each side:q = 2/p - m

A. Q. M. Bazlul Karim was born in 1920.

I think so.Sum = m + q

Personal Protective Equipment

According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 1 words with the pattern Q--M-Q-M. That is, eight letter words with 1st letter Q and 4th letter M and 6th letter Q and 8th letter M. In alphabetical order, they are: qaimaqam

If M P and Q are collinear and MP plus PQ equals MQ then P is between M and Q.

Depends if your name begins with 'A to M' or 'M to Q'. 'A to M' = Run 'M to Q' = Ran Hope this helps! :D

According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 4 words with the pattern -Q---M--. That is, eight letter words with 2nd letter Q and 6th letter M. In alphabetical order, they are: squawman squawmen squirmed squirmer

If a number can be divisible by 2 twice( ei, 48 in half is 24 and 24 can be divided in half. But you can check, without doing any dividing. If the last 2 digits (the tens and ones place digits) is divisible by 4, then the whole number is divisible by 4. How to tell if the last two digits are divisible by 4: add the ones digit to twice the tens digit: if this sum is divisible by 4, then so is the original. This sum can be repeated until a single digit remains. IF this digit is 4 or 8, then the original number is divisible by 4. So if you have a number 975239806723498658859303524, then the last two digits are 24, which is divisible by 4 and the entire number is divisible by 4 (4 + 2×2 = 8 which is 4 or 8, so 24 is divisible by 4). Why this works: Suppose you have a whole number M. Rewrite the number as M = 100*P + Q, where P & Q are whole numbers. Note that Q represents the last two digits, and P is the rest of the number. Now divide this by 4: M/4 = (100*P + Q)/4 = 100*P/4 + Q/4 = 25*P + Q/4. So since P is a whole number, then 25*P is a whole number, and if Q/4 is a whole number, then [M/4 = 25*P + Q/4], which is the sum of two whole numbers is also a whole number, so M is divisible by 4. Let M = 324, so P = 3, and Q = 24. 324 = 100*3 + 24, and 324/4 = 25*3 + 24/4 = 75 + 6 = 81. So 324 is divisible by 4. A number which is divisible by 4 is a multiple of 4