If M P and Q are collinear and MP plus PQ equals MQ then P is between M and Q.
m m
The answer depends on what and where the points are. Since you have provided no information on that it is not possible to give a sensible answer.
m= (y2 - y1)/(x2 - x1) m= (4 - 0)/(2 - 0) m = 2
Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
The slope (m) = (delta y)/(delta x) m= (y2-y1)/(x2-x1) Given two points A(a,b) C(c,d) if A is the starting point (x1,y1) and C is the ending point (x2,y2) then m= (d-b)/(c-a) OR if C is the starting point then, m=(b-d)/(a-c) both will give you the same answer.
Draw and label a line with collinear points J, K, L, M, N, and O. J and O are not between any points
If points m, n, o, and p are arranged such that three of them lie on a straight line, there are two possible scenarios: either three points (e.g., m, n, o) are collinear and the fourth point (p) is not, or all four points are collinear. In the first case, there is one line formed by the three collinear points, and the fourth point can form additional lines with any two of the other three points. Therefore, if only three are collinear, there are multiple lines; if all four are collinear, there is just one line.
m, the slope, is calculated using the following formula. m=y2-y1 ------- x2-x1 where y are the 2 vertical points, and x are the horizontal points. In other words, rise over run.
M is worth 3 points.
what are the disease's in M&M's
The letter M is worth 3 points.
To find a third point on a line defined by two points, you can use the formula for the line's slope. First, calculate the slope (m) using the two points (x1, y1) and (x2, y2) with the formula ( m = (y2 - y1) / (x2 - x1) ). Then, using the slope, you can find a third point by choosing a value for x (or y) and using the line equation ( y - y1 = m(x - x1) ) to solve for the corresponding y (or x) value. This will give you a third point that lies on the same line.
First, you calculate the slope between the two points (difference of y / difference of x). Then you can use the equation, using one of the points (x1, y1): y - y1 = m(x - x1) Just replace x1 and y1 with the coordinates of the point, and m with with the slope.
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To find the equation of the line passing through the points (-1, -3) and (2, 1), we first calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the points, we get ( m = \frac{1 - (-3)}{2 - (-1)} = \frac{4}{3} ). Using the point-slope form ( y - y_1 = m(x - x_1) ) with one of the points, say (-1, -3), the equation becomes ( y + 3 = \frac{4}{3}(x + 1) ), which simplifies to ( y = \frac{4}{3}x + \frac{1}{3} ).
To find the equation of the line passing through the points (3, 20) and (-9, 6), we first calculate the slope (m) using the formula (m = \frac{y_2 - y_1}{x_2 - x_1}). Substituting the points, we have (m = \frac{6 - 20}{-9 - 3} = \frac{-14}{-12} = \frac{7}{6}). Using the point-slope form (y - y_1 = m(x - x_1)), we can use one of the points, say (3, 20), to get the equation: (y - 20 = \frac{7}{6}(x - 3)). Simplifying this gives the line's equation in slope-intercept form.
To convert two points into slope-intercept form (y = mx + b), first calculate the slope (m) using the formula (m = \frac{y_2 - y_1}{x_2 - x_1}), where ((x_1, y_1)) and ((x_2, y_2)) are the given points. Next, use one of the points and the slope to solve for the y-intercept (b) by substituting the values into the equation. Finally, rewrite the equation in the form y = mx + b using the calculated slope and y-intercept.