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If M P and Q are collinear and MP plus PQ equals MQ then P is between M and Q.

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15y ago

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Put letters j o m k l n l j m k l on collinear line?

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If points m, n, o, and p are arranged such that three of them lie on a straight line, there are two possible scenarios: either three points (e.g., m, n, o) are collinear and the fourth point (p) is not, or all four points are collinear. In the first case, there is one line formed by the three collinear points, and the fourth point can form additional lines with any two of the other three points. Therefore, if only three are collinear, there are multiple lines; if all four are collinear, there is just one line.


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How do you find third point of line out of 2 points?

To find a third point on a line defined by two points, you can use the formula for the line's slope. First, calculate the slope (m) using the two points (x1, y1) and (x2, y2) with the formula ( m = (y2 - y1) / (x2 - x1) ). Then, using the slope, you can find a third point by choosing a value for x (or y) and using the line equation ( y - y1 = m(x - x1) ) to solve for the corresponding y (or x) value. This will give you a third point that lies on the same line.


How do you find The equation of a line given two points needed?

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To find the equation of the line passing through the points (-1, -3) and (2, 1), we first calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the points, we get ( m = \frac{1 - (-3)}{2 - (-1)} = \frac{4}{3} ). Using the point-slope form ( y - y_1 = m(x - x_1) ) with one of the points, say (-1, -3), the equation becomes ( y + 3 = \frac{4}{3}(x + 1) ), which simplifies to ( y = \frac{4}{3}x + \frac{1}{3} ).


Which equation represents the line passing through the points (320 and (-96)?

To find the equation of the line passing through the points (3, 20) and (-9, 6), we first calculate the slope (m) using the formula (m = \frac{y_2 - y_1}{x_2 - x_1}). Substituting the points, we have (m = \frac{6 - 20}{-9 - 3} = \frac{-14}{-12} = \frac{7}{6}). Using the point-slope form (y - y_1 = m(x - x_1)), we can use one of the points, say (3, 20), to get the equation: (y - 20 = \frac{7}{6}(x - 3)). Simplifying this gives the line's equation in slope-intercept form.


How do you change two points into slope-intercept form?

To convert two points into slope-intercept form (y = mx + b), first calculate the slope (m) using the formula (m = \frac{y_2 - y_1}{x_2 - x_1}), where ((x_1, y_1)) and ((x_2, y_2)) are the given points. Next, use one of the points and the slope to solve for the y-intercept (b) by substituting the values into the equation. Finally, rewrite the equation in the form y = mx + b using the calculated slope and y-intercept.