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The equation 4R + 3s + 2r = 6r + 3s is an example of the distributive property of addition, where the term 4R is being distributed over the sum of 2r and 6r.
To see this more clearly, we can rewrite the equation as:
4R + 3s + 2r = (4R + 6r) + 3s
Notice how the terms 4R and 6r are combined and the distributive property allows us to simplify the left-hand side of the equation.
What else can I help you with?
What is -2 - 6r plus 4r?
-2 - 2r or -2(1 - r)
What is the answer for 6R - 12 equals 2R plus 36?
Type your answer here... 6R-12 = 2R + 36 subtract 2R from both sides 4R -12 = 36 add 12 to both sides 4R = 48 divide both sides by 4 R = 12
How do you Simplify 2r-4s plus 3s-8r?
-6r - s
Use the identity below to complete the tasks:a3 + b3 = (a + b)(a2 - ab + b2)Use the identity for the sum of two cubes to factor 8q6r3 + 27s6t3.What is a What is b?
Below ^ denotes power. 8q^6r^3=(2q^2r)^3 denote as a^3 and find a=2q^2r 27s^6t^3=(3s^2t)^3 denote as b^3 and find b=3s^2t Now 8q^6r^3+27s^6t^3=a^3+b^3 = (a+b)(a^2-ab+b^2) | substitute back =(2q^2r+3s^2t)(4q^4r^2-6q^2rs^2t+9s^4t^2). Notice (2q^2r)^2=4q^4r^2 (3s^2t)^2=9s^4t^2. Hence 8q^6r^3+27s^6t^3=(2rq^2+3ts^2)(4r^2q^4-6rts^2t^2+9t^2s^4), a=2q^2r and b=3s^2t.
What is the difference between sodium hyaluronate and sodium chloride?
Sodium chloride is NaCl.Sodium hyaluronate has a very long and complicate name:Sodium (2S,3S,4R,5R,6R)-3- [(2S,3R,4R,5S,6R)-3-acetamido-4-[(2R,3R,4S,5S,6S)-6-carboxy-3,4,5-trihydroxyoxan-2-yl]oxy-5-hydroxy-6-(hydroxymethyl)oxan-2-yl]oxy-6-[(2R,3R,4R,5S,6R)-3-acetamido-2,5-dihydroxy-6-(hydroxymethyl)oxan-4-yl]oxy-4,5-dihydroxyoxane-2-carboxylic acid.
What is -6r-4r?
the answer is -10r
0.3 times 2r- 0.3 times3 equals 0.2r plus 0.9?
0.3(2r) - 0.3(3) = 0.2(r) + 0.9Clear parentheses:0.6r - 0.9 = 0.2r + 0.9Multiply each side by 10:6r - 9 = 2r + 9Add 9 to each side:6r = 2r + 18Subtract 2r from each side:4r = 18Divide each side by 4:r = 18/4 = 4.5
2r plus 2s equals 50 and 2r minus s equals 17?
2r + 2s = 50 2r - s = 17 therefore 4r - 2s = 34 Add so that you can eliminate one of the variables: 2r + 2s = 50 4r - 2s = 34 ---------------- 6r + 0s = 84 Solve for r: 6r = 84 r = 14 Substitute r into one of the original equations: 2(14) + 2s = 50 28 + 2s = 50 2s = 22 s = 11 Doublecheck with the other original equation: 2(14) - 11 = 28 - 11 = 17
What is -2r(8r 5)?
6r
What is the answer forSimplify by combining like terms 3q plus 4r-s plus 5q-6r plus 2s?
3q+4r-s+5q-6r+2s
What is 9r-5r-6r equals?
-2r
22 plus 6r equals 4r plus 38?
r=8
