2r + 2s = 50
2r - s = 17 therefore 4r - 2s = 34
Add so that you can eliminate one of the variables:
2r + 2s = 50
4r - 2s = 34
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6r + 0s = 84
Solve for r:
6r = 84
r = 14
Substitute r into one of the original equations:
2(14) + 2s = 50
28 + 2s = 50
2s = 22
s = 11
Doublecheck with the other original equation:
2(14) - 11 = 28 - 11 = 17
2r + 7r - 6t - r + 7t = 8r + t
4r+4g
Presumably this is a simultaneous equation in the form of: 3r-4s = 0 2r+5s = 23 Multiply all the terms in the top equation by 2 and in the bottom equation by 3: 6r-8s = 0 6r+15s = 69 Subtract the bottom equation from the top equation: -23s = -69 Divide both sides by -23 to find the value of s remembering that a minus number divided into a minus number is equal to a plus number: s = 3 Substitute the value of s into the original equations to find the value of r: Therefore: r = 4 and s = 3
5
2r
r -31
|2r + 9| = 5 So 2r + 9 = 5 or 2r + 9 = -5 so that 2r = -4 or 2r = -14 r = -2 or r = -7
A math problem
10+r = 2r Subtract r from both sides:- r = 10
r + s = 4 and 2r + 3s = 8 multiply the first equation by 2 giving 2r + 2s = 8 subtract this from the second equation giving s = 0 So r = 4 and s = 0.
2r-1=9 2r =10 r =5
Solving for r: 16r2+18r+5=0 (2r+1)(8r+5)=0 2r+1=0 and 8r+5=0 2r=-1 .......... 8r=-5 r= -1/2 ........ r= -5/8
If: 7 -2r = 13 Then: r = -3
If: -7 = 7-2r Then: r = 7
If: C = 2r Then: r = C/2
2r + 5 - - 1 When simplified: 2r + 6
2r + 4 or 2*(r+2)