2r + 2s = 50
2r - s = 17 therefore 4r - 2s = 34
Add so that you can eliminate one of the variables:
2r + 2s = 50
4r - 2s = 34
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6r + 0s = 84
Solve for r:
6r = 84
r = 14
Substitute r into one of the original equations:
2(14) + 2s = 50
28 + 2s = 50
2s = 22
s = 11
Doublecheck with the other original equation:
2(14) - 11 = 28 - 11 = 17
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2r + 7r - 6t - r + 7t = 8r + t
4r+4g
Presumably this is a simultaneous equation in the form of: 3r-4s = 0 2r+5s = 23 Multiply all the terms in the top equation by 2 and in the bottom equation by 3: 6r-8s = 0 6r+15s = 69 Subtract the bottom equation from the top equation: -23s = -69 Divide both sides by -23 to find the value of s remembering that a minus number divided into a minus number is equal to a plus number: s = 3 Substitute the value of s into the original equations to find the value of r: Therefore: r = 4 and s = 3
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2r