Lets try to solve step by step:
Let the present age of father and son be x and y years.
5 years ago....
fathers age is x-5
sons age is y-5
By the question,
(x-5)+(y-5)=60
or, x+y-10=60
or,x+y=60+10
=70
x+y=70................................................(1)
5 years later
fathers age is x+5
sons age is y+5
By the question,
(x+5)-(y+5)=30
x-y=30
x-y=30..............................................(2)
Adding 1 and 2 we will get
x+y+x-y=70+30
2x=100
x=50
Fathers 50 is present age .
2 years after 52
Sons age (70-50)=20
2 years from now is 22.
I hope so it will provide u som help..
There is not enough information to find the father, nor his age.The sum of their ages, in y years' time will be 7b + 2y years.
son- b/t 3 and 4 dad- b/t 36 and 48
108 years Father = 72 Son = 36 (1/2 of father's) 72 + 36 = 108
6 years ago, they were 26 and 52.Now they're 32 and 58.
If she was 30 when her son was born, then the minimum age she can be is 40 because the minimum age the kid can be is 10. That would make the father 50 because 40 + 10=50. 50+50=100.
The father is 40 and his son is 14, a difference of 26 years and their combined ages equal 54.
Ages are 25 and 20, so difference = 5 years.
There is not enough information to find the father, nor his age.The sum of their ages, in y years' time will be 7b + 2y years.
46
Answer: 30 (Dad) & 6 (Son) 2 years later they will be 32 & 8 which equals 40.
son- b/t 3 and 4 dad- b/t 36 and 48
He is 67.
14
10
108 years Father = 72 Son = 36 (1/2 of father's) 72 + 36 = 108
If the average of 6 birds' age is 10, and the difference in the youngest and oldest is 8 years, the ages of the 6 birds are 6, 10, 12, 17, 18, and 14.
6 years ago, they were 26 and 52.Now they're 32 and 58.