Lets try to solve step by step:
Let the present age of father and son be x and y years.
5 years ago....
fathers age is x-5
sons age is y-5
By the question,
(x-5)+(y-5)=60
or, x+y-10=60
or,x+y=60+10
=70
x+y=70................................................(1)
5 years later
fathers age is x+5
sons age is y+5
By the question,
(x+5)-(y+5)=30
x-y=30
x-y=30..............................................(2)
Adding 1 and 2 we will get
x+y+x-y=70+30
2x=100
x=50
Fathers 50 is present age .
2 years after 52
Sons age (70-50)=20
2 years from now is 22.
I hope so it will provide u som help..
There is not enough information to find the father, nor his age.The sum of their ages, in y years' time will be 7b + 2y years.
son- b/t 3 and 4 dad- b/t 36 and 48
108 years Father = 72 Son = 36 (1/2 of father's) 72 + 36 = 108
6 years ago, they were 26 and 52.Now they're 32 and 58.
Let the father's age be ( F ) and the son's age be ( S ). According to the problem, we have the equations: ( F + S = 45 ) ( F - 5 = 6(S - 5) ) From the second equation, we can express ( F ) in terms of ( S ) and substitute into the first equation. Solving these equations gives ( F = 30 ) and ( S = 15 ). Thus, the father is currently 30 years old, and the son is 15 years old.
The father is 40 and his son is 14, a difference of 26 years and their combined ages equal 54.
Ages are 25 and 20, so difference = 5 years.
There is not enough information to find the father, nor his age.The sum of their ages, in y years' time will be 7b + 2y years.
46
Answer: 30 (Dad) & 6 (Son) 2 years later they will be 32 & 8 which equals 40.
son- b/t 3 and 4 dad- b/t 36 and 48
14
He is 67.
10
108 years Father = 72 Son = 36 (1/2 of father's) 72 + 36 = 108
Nothing. There is a 1000 years difference between the two ages. The fall of Rome in 410 AD led to the middle ages which in turn led to the Renaissance.
6 years ago, they were 26 and 52.Now they're 32 and 58.