There is not enough information to find the father, nor his age.The sum of their ages, in y years' time will be 7b + 2y years.
Is this a trick question? The age is the sun is approx 4.6 billion years!
6 years ago, they were 26 and 52.Now they're 32 and 58.
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son- b/t 3 and 4 dad- b/t 36 and 48
a father is 30 years older than his son.in 12 years,the men will be three times as old as his son.find their present ages.
Answer: 30 (Dad) & 6 (Son) 2 years later they will be 32 & 8 which equals 40.
son is 10, father is 33
There is not enough information to find the father, nor his age.The sum of their ages, in y years' time will be 7b + 2y years.
The ages are 8 and 4
Is this a trick question? The age is the sun is approx 4.6 billion years!
Total ages at present = 42 Total ages in 10 years = 52 Fractions then 15/26 x 52 and 11/26 x 52, ie 30 and 22 so ages now 25 and 17
The father is 40 and his son is 14, a difference of 26 years and their combined ages equal 54.
G = Girl's present age F = Father's present age 4G = F G +7 = 1/2 (F - 12) By substitution: G + 7 = 1/2 (4G - 12); G = 13 By plugging in the value of G = 13; F = 52 The girl is presently 13 and her father is 52.
Ages are 25 and 20, so difference = 5 years.
6 years ago, they were 26 and 52.Now they're 32 and 58.
He is 67.