Let the father's age be ( F ) and the son's age be ( S ). According to the problem, we have the equations:
From the second equation, we can express ( F ) in terms of ( S ) and substitute into the first equation. Solving these equations gives ( F = 30 ) and ( S = 15 ). Thus, the father is currently 30 years old, and the son is 15 years old.
There is not enough information to find the father, nor his age.The sum of their ages, in y years' time will be 7b + 2y years.
Is this a trick question? The age is the sun is approx 4.6 billion years!
6 years ago, they were 26 and 52.Now they're 32 and 58.
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son- b/t 3 and 4 dad- b/t 36 and 48
a father is 30 years older than his son.in 12 years,the men will be three times as old as his son.find their present ages.
Answer: 30 (Dad) & 6 (Son) 2 years later they will be 32 & 8 which equals 40.
son is 10, father is 33
There is not enough information to find the father, nor his age.The sum of their ages, in y years' time will be 7b + 2y years.
The ages are 8 and 4
Is this a trick question? The age is the sun is approx 4.6 billion years!
Total ages at present = 42 Total ages in 10 years = 52 Fractions then 15/26 x 52 and 11/26 x 52, ie 30 and 22 so ages now 25 and 17
The father is 40 and his son is 14, a difference of 26 years and their combined ages equal 54.
G = Girl's present age F = Father's present age 4G = F G +7 = 1/2 (F - 12) By substitution: G + 7 = 1/2 (4G - 12); G = 13 By plugging in the value of G = 13; F = 52 The girl is presently 13 and her father is 52.
Ages are 25 and 20, so difference = 5 years.
6 years ago, they were 26 and 52.Now they're 32 and 58.
He is 67.