3.5 ft
To find the length of the diagonal of a square patch of sheetrock with a perimeter of 10 feet, first calculate the length of one side. The perimeter ( P ) of a square is given by ( P = 4s ), where ( s ) is the side length. So, ( s = \frac{10}{4} = 2.5 ) feet. The diagonal ( d ) can be calculated using the formula ( d = s\sqrt{2} ), which gives ( d \approx 2.5 \times 1.414 \approx 3.54 ) feet. Thus, the length of the diagonal is closest to 3.54 feet.
it is impossible for a diagonal of a rhombus to be the same length as its perimeter
The length of the other diagonal works out as 12cm
The length of one diagonal is not sufficient to determine its sides and so its perimeter.
Measure the length and the width. Or if you are feeling particularly energetic, then one of them and the diagonal.
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
The length, width, height, thickness, diagonal, perimeter, are some characteristics.
The perimeter of this square is 56.569 meters.
The answer to this question depends on what characteristic of a rhombus you are measuring: the length of its sides, its perimeter, area, length of diagonal, its acute angles, its obtuse angles, or something else.
~26.16 units.
The perimeter of a square with a diagonal length of 24 square root 2 millimeters (33.94 mm) is: 96 mm