Q: The perimeter of a rhombus is 40cm and the length of one diagonal is 16cm find the length of the other diagonal?

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That will depend on the length of the other diagonal because area of a rhombus is 0.5*product of its diagonals.

It is a rhombus or a kite

A kite is different from a rhombus in a few ways: * Kites have two pairs of adjacent legs that are congruent, and each pair is a separate length; a rhombus has four congruent sides. * A kite and rhombus both have perpendicular diagonals, but in a kite, only the diagonal between the pairs of sides (the diagonal between two sides of different length) is bisected; the other is not. Also, the diagonals bisect all of the angles of a rhombus; only the angles in the middle of the pairs of sides (angles with two legs of equal length) are bisected. * Only the angles between the pairs of sides are congruent in a kite; a rhombus has 2 pairs of congruent opposite angles. You can also think of a rhombus as a combination between a kite and a parallelogram, the same way you can think of a square as a combination of a rectangle and a rhombus. Hope this helps!

Parallelogram is the answer you Knowas well as rectangleAlso a square, and a rhombus

A rhombus has four sides of equal length.

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Constructing the figure, we find the other diagonal to have length 10.The area of the rhombus would thus be 10x8x0.5=40

That will depend on the length of the other diagonal because area of a rhombus is 0.5*product of its diagonals.

The diagonals of a rhombus are perpendicular and intersect each other at right angles which is 90 degrees

There is no relationship between the perimeter and the area of a rhombus. Take a rhombus with all 4 sides = 2 units. Therefore the perimeter is 8 units. There are an infinite number of possible areas for this rhombus. The largest possible area will be when the rhombus approaches the shape of a square = 4 square units. The smallest area will be when the one diagonal approaches 0 units and the other diagonal approaches 4 units (squashed almost flat). So two very extreme areas can have the same perimeter, including all those areas in-between.

One diagonal of a rhombus is larger than the other diagonal but both diagonals intercept each other at right angles.

Rhombus Area = side x height = 6 cm x 4 cm = 24 cm2In the right triangle formed by the side and the height of the rhombus, we have:sin (angle opposite to the height) = height/side = 4 cm/6cm = 2/3, so thatthe angle measure = sin-1 (2/3) ≈ 41.8⁰.In the triangle formed by two adjacent sides and the required diagonal, which is opposite to the angle of 41.8⁰ of the rhombus, we have: (use the Law of Cosines)diagonal length = √[62 + 62 -2(6)(6)cos 41.8⁰] ≈ 4.3Thus, the length of the other diagonal of the rhombus is about 4.3 cm long.

Given: The area of the rhombus is 120 square feet The diagonal of the rhombus is 16 feet think of the rhombus being two identical triangles, connected at their base which is 16 feet long. Each of them would then have an area of 60 feet. Now, in a triangle, area = (base * height) / 2 the area is already given as 60, and the base as 16 we can say then: 60 = (16 * h) / 2 ∴60 = 8h ∴h = 7.5 Now, that 7.5 is half the length of the rhombus (as it's the height of one of our triangles, which each are half our rhombus). So we know that that the other diagonal on the rhombus is twice that. In other words, the answer is 15.

Area=ba where b=base (any side), and a=altitude, the perpendicular length from the base to the opposite sideORArea= (d1*d2)/2 where d1 is the diagonal and d2 is the other diagonal

The main difference between a square and a rhombus is that a square has all its angles equal to 90 degrees and a rhombus does not. A square has 4 lines of symmetry while rhombus only has 2. The diagonal lengths of a square are of the same measure. Rhombus diagonal lengths are of different measures. They are both a quadrilateral, all sides are equal in length, and opposite sides are parallel to each other.

Diagonals of a rhombus are perpendicular so the product is the area. If x is the smaller diagonal, the longer is 4x, and the area if 4x2.

Let the other diagonal be x If: 0.5*12*x = 30 then x = 60/12 => x = 5 The rhombus has four interior right angle triangles with lengths of 6 cm and 2.5 cm Using Pythagoras each equal sides of the rhombus works out as 6.5 cm Perimeter: 4*6.5 = 26 cm

The answer depends on what information you have about the rectangle: the area and width, or width and diagonal, area and perimeter or some other measures.