At 45 degrees.
Yay! I got a proof done, check the link below, back to studying derivations for a infinite line of charge, ewww.
The Related Question may answer yours. (See below left.)
If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.
The speed of an object falling from a great height is measured in meters per second per second until it reaches terminal velocity (maximum downward speed).
'Maximum height' means the exact point at which the velocity changes from upward to downward. At that exact point, the magnitude of the velocity is zero. It doesn't matter what the velocity was when it left your hand. That number determines the maximum height, but the velocity at that height is always zero. --------------------------------------------------------- Thus using the formula: (vf)e2 = (vi)e2+2*a*d vf = final velocity = 0 m/s vi = initial velocity = 10 m/s a = acceleration = gravity = - 9.81 m/s/s d = displacement (distance) = ? e is designating that the next figure is an exponent in the formula So the formula is: (0)e2 = (10)e2 + (2 * -9.81 * d) 0 = 100 + -19.62d adding 19.62d to both sides of the equation 19.62d = 100 dividing by 19.62 d = ~ 5.097 meters
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
Yes.
The horizontal component of a projectile's velocity doesn't change, until the projectile hits somethingor falls to the ground.The vertical component of a projectile's velocity becomes [9.8 meters per second downward] greatereach second. At the maximum height of its trajectory, the projectile's velocity is zero. That's the pointwhere the velocity transitions from upward to downward.
There are two different ways of looking at this. The maximum length from end to end from the telecommunications closet to the wor karea device is 100 meters. The horizontal cable itself is usually a maximum of 90 meters, with 10 meters maximum from the wall plate to the device in the work area.
18
swagger
It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.
In the case of an object thrown, batted, teed off, or dropped, its acceleration at the instant of its maximum velocity is 9.8 meters per second2 downward.
90 meters
You kicked the rock with an initial velocity of 3.4 m/s.
90 Meters+ 10 meters for running cables so 100 meters is the total.
There is not enough information to answer the question. The initial velocity of the car is not given. Also, the "it finally" at the end of the question does not make sense.
In the absence of air resistance, the force of gravity has no effect on the horizontal component of a projectile's velocity, and causes the vertical component of its velocity to increase by 9.8 meters (32.2 feet) per second downward for every second of its flight.
If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.