If the scale is calibrated in tenths of a kilogram I do not see how you can estimate to the nearest two hundredths of a kilogram!
The calibration allows you to measure mass (in kilograms) to 1 decimal place. For masses less than 10 kg, that mean 2 significant figures. For masses of 10 kg or more but less than 100 kg, you can give the information to 3 sf and for masses of 100 kg or more, 3 sf.
You would need to record to the 0.1 cm, then estimate the next significant figure. So you should have a measurement to the 0.01 cm.
The rules for identifying significant figures when writing or interpreting numbers are as follows: All non-zero digits are considered significant. For example, 91 has two significant figures (9 and 1), while 123.45 has five significant figures (1, 2, 3, 4 and 5). Zeros appearing anywhere between two non-zero digits are significant. Example: 101.1203 has seven significant figures: 1, 0, 1, 1, 2, 0 and 3. Leading zeros are not significant. For example, 0.00052 has two significant figures: 5 and 2. Trailing zeros in a number containing a decimal point are significant. For example, 12.2300 has six significant figures: 1, 2, 2, 3, 0 and 0. The number 0.000122300 still has only six significant figures (the zeros before the 1 are not significant). In addition, 120.00 has five significant figures since it has three trailing zeros.
int num = 12345; int lastDigit = num % 10; // = 5
Any time an experiment isn't quantitative, you don't need exact masses. Generally though, three significant digits makes a good rule of thumb for accuracy.
It is not possible to give any estimate for x given only the information in the question.
no. you can estimate by using an oven therometer
50000
to 1 significant digit: 8000 2 significant digits: 7700 3 significant digits: 7660 4 significant digits: 7656. 5 significant digits: 7656.0 6 significant digits: 7656.00 and so on and so forth for forever..........
4.11, to the justified number of significant digits.
Given conditions of standard temperature and pressure, and measuring in standard units with calibrated mensuration devices in a controlled laboratory environment, the best current estimate is precisely 32 of them.
For an "estimate", I would suggest rounding it to one or two significant digits.
8.235
No, 'estimate' means to guess the value of something, while 'round' means either circular or is a process for truncating a value to fewer significant figures.
For a quick estimate, you would usually round to one, sometimes to two, significant digits. One significant digit means discarding all digits after the first, i.e., converting them to zero (and rounding the remaining digit up or down as appropriate).
The calculator already gives you a square root (or other root) with 8 or 10 significant digits, and does so quickly; there is no need to "estimate". However, you can round the result if you like.
You would need to record to the 0.1 cm, then estimate the next significant figure. So you should have a measurement to the 0.01 cm.
Significant variables are the variables whose change will alter or affect the outcome of the experiment. Variables that are not significant may also alter the outcome, but this change is a statistical error, not a systematic change. For example if you are trying to estimate how much food will be consumed in an event, a variable is how many people will attend the event and another is how tall are the people that attend it. The first variable is significant, whereas the latter isn't.