If the scale is calibrated in tenths of a kilogram I do not see how you can estimate to the nearest two hundredths of a kilogram!
The calibration allows you to measure mass (in kilograms) to 1 decimal place. For masses less than 10 kg, that mean 2 significant figures. For masses of 10 kg or more but less than 100 kg, you can give the information to 3 sf and for masses of 100 kg or more, 3 sf.
int num = 12345; int lastDigit = num % 10; // = 5
The significant figures in a measurement include all known digits plus one estimated digit. All non-zero digits are considered significant, zeros between non-zero digits are significant, and zeros at the end of a number and after a decimal point are significant.
The best estimate suggests that about 50-60% of the variation in intelligence can be explained by genetics. This means that genetic factors play a significant role in determining an individual's level of intelligence, but environmental factors also play an important role.
Two significant figures are justified in this measurement. Since the measuring device ruler has smallest divisions of 0.1 cm, the uncertainty lies in the last digit. The measurement falls between 9.0 cm and 10.0 cm, so the two digits, 9 and 0, are significant.
To increase the number of significant figures in a measurement, you can estimate between the smallest markings on the measuring device. For example, if a device measures to the nearest 0.1 unit, you can estimate to the nearest 0.01 unit to increase the number of significant figures.
no. you can estimate by using an oven therometer
50000
to 1 significant digit: 8000 2 significant digits: 7700 3 significant digits: 7660 4 significant digits: 7656. 5 significant digits: 7656.0 6 significant digits: 7656.00 and so on and so forth for forever..........
4.11, to the justified number of significant digits.
Given conditions of standard temperature and pressure, and measuring in standard units with calibrated mensuration devices in a controlled laboratory environment, the best current estimate is precisely 32 of them.
For an "estimate", I would suggest rounding it to one or two significant digits.
8.235
No, 'estimate' means to guess the value of something, while 'round' means either circular or is a process for truncating a value to fewer significant figures.
For a quick estimate, you would usually round to one, sometimes to two, significant digits. One significant digit means discarding all digits after the first, i.e., converting them to zero (and rounding the remaining digit up or down as appropriate).
The calculator already gives you a square root (or other root) with 8 or 10 significant digits, and does so quickly; there is no need to "estimate". However, you can round the result if you like.
236+710 = 946. Rounded to 2 significant digits, that is 950, rounded to one sd, it is 900.
To quickly estimate a sum, you round both numbers to the nearest easy significant figure. In this case 8.91 can be rounded up to 9. 1.16 can be rounded down to 1. You then complete the sum with the rounded figures. 9+1 = 10, so the estimate of 8.91+1.16 is 10.