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The speed of the stream is 3mph and that of the boat is 8mph.

If vs is the speed of the stream, in mph and vb is the speed of the boat in mph, then:

  • upstream speed = vb - vs mph
  • downstream speed = vb + vs mph

Thus:

30/(vb-vs) + 44/(vb+vs) = 10

40/(vb-vs) + 55/(vb+vs) = 13

Multiplying both equations by (vb2-vs2) gives:

30(vb+vs) + 44(vb-vs) = 10(vb2-vs2)

40(vb+vs) + 55(vb-vs) = 13(vb2-vs2)

which rearrange to:

vb2-vs2 = (74vb - 14vs) / 10

vb2-vs2 = (95vb - 15vs) / 13

so, using the equality:

(74vb - 14vs) / 10 = (95vb - 15vs) / 13

12vb = 32vs

vb = 8/3 vs

thus using the first equation and the equality just worked out:

10((8/3 vs)2 - vs2) = 74(8/3 vs) - 14vs

vs10(64 / 9 - 1) = 74 x 8 / 3 - 14

vs10(55)/9 = (592 - 42)/3

vs550/9 = 550/3

vs = 3 mph

vb = 8/3 x 3 mph = 8 mph

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Q: A boat goes upstream 30 miles and downstream 44 miles in 10 hours It also goes upstream 40 miles and downstream 55 miles in 13 hours Find the rates of the stream and of the boat?
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