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Call the speed in miles per hour of the cabin cruiser c and of the power boat p. From the problem statement, p = c + 5. From the problem statement and the physical law that distance equals the product of speed and time, called t, 20 = ct and 40 = pt. Multiplying the first of these two latter equations by 2 yields 40 = 2ct, and from the lattermost equation, 2ct = pt, since both are equal to 40. Dividing this last equation by t (which can not be zero since covering any finite distance requires a nonzero time) yields 2c = p, and from the first equation given, 2c = c + 5, or c = 5, p = 10, both in miles per hour.

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Q: A cabin cruiser travels 20 miles in the same time that a power boat travels 40 miles The cruiser travels 5 mph slower than the power boat Find the speed of each boat?
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