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A car starts from rest and reaches 20 ms in 10 seconds The average acceleration of the car in ms2 is?
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∙ 13y ago
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If a car starts from rest and after 6 seconds it is moving at 42 ms what is the car's average acceleration?
If a car is moving 42 meters per second after 6 sectons, the average acceletion is 7 meters per second per second. It is an average, given two points of data, and it is not the instantaneous acceleration at any point in time.
What is the acceleration of a ball that starts from rest and rolls down a ramp and gains speed at 25 ms in 5 seconds?
Average acceleration during a time interval = (change in speed) divided by (time for the change) =(25) / (5) = 5 meters per second2
What is speed of object at 3 seconds given an acceleration of 16 feet per second squared for 3 seconds?
I assume the object starts from rest. The speed will be 16*3 which is 48m/s
What is the final velocity of a train that starts at rest and accelerates for 15.0 seconds at an average acceleration of 2.40 meter per second squared?
Unknown: final velocity, vfKnown:initial velocity, vi = 0m/stime, t = 15.0saverage acceleration, a = 2.40m/s2Equation:vf = vi + atSolution:vf = 0 + 2.40m/s2 x 15.0s = 36.0m/s
A train starts from rest and increases its speed uniformly for the three minutes In that time it reaches 150 kilometers per hour What is its acceleration?
veliocity = = acceleration x time v = at v = 150 km /hr = 150/60 km/minute t = 3 minutes a = v/t = 150/60/3 = 5/6 km/min/min = .833 km/min/min
What is the average acceleration of a car that starts at rest and then moves straight ahead reaching 18 meters per second in 12 seconds?
It is accelerating at 1.2m/s per second.
A car starts at rest and attains a velocity of 15 meters per second in 5 seconds what is its acceleration?
The average acceleration is given by the expression a ∆v/∆t (15 m/s)/5s 3m/s2 where a is acceleration, v is velocity, and t is time. ∆ (final-initial) value.
If a car starts from rest and after 6 seconds it is moving at 42 ms what is the car's average acceleration?
If a car is moving 42 meters per second after 6 sectons, the average acceletion is 7 meters per second per second. It is an average, given two points of data, and it is not the instantaneous acceleration at any point in time.
What is the acceleration of a ball that starts from rest and rolls down a ramp and gains speed at 25 ms in 5 seconds?
Average acceleration during a time interval = (change in speed) divided by (time for the change) =(25) / (5) = 5 meters per second2
What is Coach Whites acceleration if he is known for rapid acceleration and he starts up from a stop sign and reaches thirteen meters per second in point forty five seconds show your work?
What do you mean "show your work" ? ! ?Did this question come from a homework assignment or something ?That's not an acceptable use of this website.Coach White's acceleration is 28.89 meters per second2, which is almost 3 G's.
If a car starts from rest and travels a distance of 100 meters in 10 seconds what is the car acceleration?
2.0 m/s^2
What is the acceleration of an object that starts stopped and after 5 seconds is going 25mm per hour?
the acceleration is increasing speed Acceleration = velocity change / time velocity change = 0 to 25 mm/hr = 25 mm/hr time = 5 seconds therefore acceleration = 25/5 mm/hr per second = 5 mm per hour per second.
What is the acceleration of a body which starts from rest and travels 87.5 m in 5 seconds?
distance = 1/2 acceleration x time squared; acceleration is 7 m/s/s
What is speed of object at 3 seconds given an acceleration of 16 feet per second squared for 3 seconds?
I assume the object starts from rest. The speed will be 16*3 which is 48m/s
What is the final velocity of a train that starts at rest and accelerates for 15.0 seconds at an average acceleration of 2.40 meter per second squared?
Unknown: final velocity, vfKnown:initial velocity, vi = 0m/stime, t = 15.0saverage acceleration, a = 2.40m/s2Equation:vf = vi + atSolution:vf = 0 + 2.40m/s2 x 15.0s = 36.0m/s
A driver starts his parked car and within 5 seconds reaches a velocity of 54 km per hour as he travels east what is his acceleration?
vf=54 km/hr vi=0km/hr t=5sec/0.001hr a=5400 km/hr 54km/hr- 0km/hr --------------------- 0.001 hr
A ball starts at rest accelerates uniformly and travels 250m in 5 seconds What is the final velocity and the acceleration of the ball?
Average speed = (250 / 5) = 50 meters per second.Initial speed = 0Final speed = 100 m/sAcceleration = (100 / 5) = 20 m/s2===> Must be a rocket-propelled ball; its acceleration is 2G !
