vf=54 km/hr vi=0km/hr t=5sec/0.001hr a=5400 km/hr 54km/hr- 0km/hr --------------------- 0.001 hr
Acceleration is zero since 55 mph is velocity and it is constant. Acceleration is defined as the rate of change in velocity. The speed is the absolute value of velocity so it is also 55.
7.5
3.00 m/s
Calculation of deceleration the speeds at two points in time.
1.7 miles per hour.
Acceleration = Change in Velocity / Change in Time a = (Final Velocity - Initial Velocity) / (Final Time - Initial Time) = (55-0)/(5-0) = 55/5 a = 11 m/s^2
To calculate the distance traveled while the velocity is increasing, you can use the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. In this case, the initial velocity is 75 m/s, the final velocity is 145 m/s, the acceleration is constant, and the time is 15 seconds. Plugging these values into the formula will give you the distance the plane travels during the acceleration period.
Positive acceleration.
To find acceleration, we use the formula a = (vf - vi) / t, where vf is the final velocity, vi is the initial velocity, and t is the time. Given that the object travels a distance of 100m in 10 seconds, its average velocity is 10 m/s. Thus, the acceleration is (10 m/s - 0 m/s) / 10 s = 1 m/s^2. The magnitude of the acceleration is 1 m/s^2.
The acceleration of an object that travels in a constant straight line velocity is zero.
The final velocity can be calculated using the formula final velocity = initial velocity + (acceleration * time). Since the ball starts at rest, the initial velocity is 0. The final velocity = 0 + (acceleration * 5). To find the acceleration, you can use the formula acceleration = (final velocity - initial velocity) / time. The final velocity is unknown, but we just calculated the final velocity is equal to 5 times the acceleration, so acceleration = (final velocity - 0) / 5. Substituting the final velocity = 5 times the acceleration into the acceleration equation, we get acceleration = (5 * acceleration - 0)/5. Solving for acceleration, we get acceleration = 1 m/s^2. The final velocity is 5 m/s.
First you need to find the two different speeds of the car which is the distance/time. We find that the car first travels at an average of 6ms-1 and then after accelerating has a speed of 10ms-1. Acceleration is the rate of change of velocity over time, our change of velocity being 10-6=4ms-1 and the change in time being stated as 3 seconds we can convert this into... (4/3)ms-2
Acceleration is zero since 55 mph is velocity and it is constant. Acceleration is defined as the rate of change in velocity. The speed is the absolute value of velocity so it is also 55.
The initial velocity of the ball is 16 feet per second when thrown upward. The velocity decreases as the ball travels upward due to gravity until it reaches its peak and starts to fall back down.
666.67 seconds
7.5
The distance the car travels during the acceleration can be calculated using the formula: distance = (initial velocity)(time) + 0.5(acceleration)(time)^2. Plug in the values: initial velocity = 0 m/s, final velocity = 40 m/s, time = 8 s. Calculate the distance traveled during the acceleration.