vf=54 km/hr vi=0km/hr t=5sec/0.001hr a=5400 km/hr 54km/hr- 0km/hr --------------------- 0.001 hr
Acceleration is zero since 55 mph is velocity and it is constant. Acceleration is defined as the rate of change in velocity. The speed is the absolute value of velocity so it is also 55.
7.5
3.00 m/s
Calculation of deceleration the speeds at two points in time.
1.7 miles per hour.
Acceleration = Change in Velocity / Change in Time a = (Final Velocity - Initial Velocity) / (Final Time - Initial Time) = (55-0)/(5-0) = 55/5 a = 11 m/s^2
Positive acceleration.
Since acceleration is a change in velocity, if your velocity is constant (does not change), your acceleration is zero.
The acceleration of an object that travels in a constant straight line velocity is zero.
when the body travels in unequal velocity in equal intervals of time.
Acceleration is zero since 55 mph is velocity and it is constant. Acceleration is defined as the rate of change in velocity. The speed is the absolute value of velocity so it is also 55.
First you need to find the two different speeds of the car which is the distance/time. We find that the car first travels at an average of 6ms-1 and then after accelerating has a speed of 10ms-1. Acceleration is the rate of change of velocity over time, our change of velocity being 10-6=4ms-1 and the change in time being stated as 3 seconds we can convert this into... (4/3)ms-2
7.5
666.67 seconds
You can't calculate the acceleration from the information provided. The object may be traveling at constant velocity, in which case the acceleration is zero; or it may start slowly end end up faster, or vice versa, in which case the acceleration will be non-zero.
if the velocity is constant, the acceleration is zero. The acceleration is the rate at which the velocity changes, so if it stays the same, the car isn't accelerating.
No, the distance an object travels in unit time is called speed. The distance travelled per unit time in a specified direction is called velocity. The rate of change of velocity is called acceleration.