0
A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid how much of the second 30 percent solution is needed to make a 400L solution that is 62 percent acid?
Wiki User
∙ 14y ago
You have enough information to obtain two equations. 1. You know that when the two liquids are added together, you need 400L total. 2. You also know that the 80% acid times its volume plus 30% acid times its volume must equal 62% times the 400L. 3. Write the two equations. Let x = volume 80% acid & y = volume 30% acid. Therefore from (1) above: x + y = 400; equation A From (2) above: .8x + .3y = .62*400; equation B 4. You have two equations, two unknowns. Solve for x & y. 5. Multiply equation A by -.8 and add equations A & B. Note x adds out to 0. Equation A now becomes -.8x - .8y = -.8*400 or -.8x - .8y = -320. -.8x - .8y = -320 +.8x + .3y = 248 (note .62*400 = 248) So -.5y = -72 and divide both sides by -.5 which yields y = 144. 6. Use equation A to solve for x since we now know "y"; x + 144 = 400 or x = 256. 7. Answer: 256L of 80% acid & 144L of 30% acid.
Wiki User
∙ 14y ago
Add your answer:
Earn +20 pts
A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid how much of the second 30 percent solution is needed to make a 400L that is 62 percent acid?
.80x+.30y=400*.62 .80x+.30y=248 This is equation one. x+y=400 x=400-y This is the second equation. .80(400-y)+.30y=248 320-.80y+.30y=248 -.50y=-72 Y=144 X=256 CHECK .80(256)+.30(144)=400(.62) 204.8+43.2=248 248=248
How many litres of 12 percent sodium hypochlorite solution are needed to make 100 Litre of 2 percent sodium hypochlorite solution?
(x L)((12%) = (100 L)(2%)x = 16.7 liters
What volume of 24 percent citric acid is needed to prepare eight 3 ounce bottles of 10 percent citric acid solution?
300 ml
How much solute is needed to prepare 150mL of a 40.0 percent lithium nitrate solution?
150 mL x 40.0 g LiNO3/100 mL solution = 60.g of solute
Why chemist needed to make industrial diamonds?
Because some industrial diamonds are not naturally-occurring diamonds, a chemist is required to formulate the recipe for materials necessary to fabricate man-made diamonds.
A chemist has one solution that is 60 percent chlorinated and another solution that is 40 percent chlorinated How much of the first 60 percent solution is needed to make a 100 L solution that is 5?
50liters
A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid How much of the second 30 percent solution is needed to make a 400 L solution that is 62 percent acid?
144liters
A chemist has one solution that is 60 percent chlorinated and another solution that is 40 percent chlorinated How much of the first 60 percent solution is needed to make a 100 L solution that is 50?
50 liters
A chemist has one solution that is 60 percent chlorinated and another solution that is 40 percent chlorinated. How much of the first 60 percent is needed to make a 100 L solution that's 50 percent?
50
A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid How much of the first 80 percent solution is needed to make a 400 L solution that is 62 percent acid?
256 liters
A chemist has one solution that is 60 percent chlorinated and another that is 40 percent chlorinated How much of each solution is needed to make a 100 liter solution that is 50 percent chlorinated?
50 Liters of the 60% solution.
When A chemist has one solution that is 80 acid and another solution that is 30 acid. How much of the first (80) solution is needed to make a 400 L solution that is 62 acid?
You need 256 litres.
How many liters of 93 percent acid solution are needed to make a 9 percent solution with 50 liters of water?
4.84
Jerry is experimenting with chemicals in the laboratory He mixes a solution that is 10 percent acid with a solution that is 30 percent acid How much of the 10 percent acid solution will be needed to m?
10 liters
A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid how much of the second 30 percent solution is needed to make a 400L that is 62 percent acid?
.80x+.30y=400*.62 .80x+.30y=248 This is equation one. x+y=400 x=400-y This is the second equation. .80(400-y)+.30y=248 320-.80y+.30y=248 -.50y=-72 Y=144 X=256 CHECK .80(256)+.30(144)=400(.62) 204.8+43.2=248 248=248
How much of a 4 percent solution is needed for a 100mg dose?
2.5ml
Mary is experimenting with chemicals in the laboratory She mixes a solution that is 10 percent acid with a solution that is 25 percent acid How much of the 10 percent acid solution will be needed to m?
16 2/3 liters
