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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: How many liters of 93 percent acid solution are needed to make a 9 percent solution with 50 liters of water?
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Jorge has four liters of 30 percent acid solution how much water should he add to make 25 percent acid solution'?

Add 0,8 L of water.

Determine the strength of a polymer solution as a percent if 80 grams of polymer are mixed with 16 liters of water?

0.1125% of polymer solution.

If in 30 liters of a solution 90 percent is alcohol then how much water needs to b added to make it 80 percent?


How can i make a 10 percent glucose solution from 50 percent glucose solution?

Let's say the total solution is 100 liters. 50 of the liters is glucose and 50 is water. We want to make the 50 glucose equal to 10% of the total solution. For that to happen, we need to make the total solution 500 liters (50 of the 500 would be a 10% solution). So we add 400 liters of water to the original 100 liter (50/50) solution. Take the total number of units and multiply by 4. Add that much in water.

How many liters of water must be added to 7 liters of a 20 percent acid solution to obtain a 10 percent acid solution?

7 liters of a 20% acid solution consists of 1.4 liters of acid (20% of the total volume) mixed with 5.6 liters of water (80% of the total volume). The amount of acid isn't going to change in the new solution. You are just going to add enough water to make it a 10% solution instead of a 20% solution. So it will be more dilute. That means that 1.4 liters of acid will represent 1/10 of the volume of the new solution. So the total volume of the new solution will be 10 x 1.4 or 14 liters. The amount of water in the new solution will be 14 - 1.4 = 12.6 liters. That is a difference of 12.6 - 5.6 = 7 liters from the amount of water you started with. So you need to add 7 liters of water to the original 20% solution to make it a 10% solution. This makes sense because if you double the amount of the mixture from 7 liters to 14 liters and the amount of acid is unchanged, the solution will be half as strong.

How do you make a 10 percent acetic acid solution from a 2 Molar solution?

10 percent acetic acid indicates there is .1 liters of acetic acid, which is equal to 1.75 moles, or 105 grams per liter. To make this solution, add 7 liters of the 2M solution to 1 liter of water, or 7/8 solution to 1/8 water.

How much water must be added to 300 liters of a solution so that its concentration change from 25 percent to 20 percent?

75 litres

How do you make a 50 percent solution?

You take y liters of the solution and put it into a bucket or container. You then put y (same amount as before) liters of water in the same container, and voila! You now have a container with 50 percentile solution, 50 percentile water.

How many ml of 50 percent dextrose solution and how many ml of water are needed to prepare 4.5 L of a 1 percent solution?

90 ml of dextrose and 4.41 litres of water.

How do you make a 5 percent starch solution?

A five percent solution of starch is quite simple to create. A solution of 20 parts water and one part of pure starch is all that is needed.

How many ml of 50 percent dextrose solution and how many ml of water are needed to prepare 100ml of 15 percent dextrose solution?

30 ml 50% dextrose + 70 ml water

How many grams of water are needed to make 100 g of a 20 percent saltwater solution?

500 Grams Of Water.

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