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What else can I help you with?
How do you make a 50 percent solution?
You take y liters of the solution and put it into a bucket or container. You then put y (same amount as before) liters of water in the same container, and voila! You now have a container with 50 percentile solution, 50 percentile water.
How much water added to convert a 10 percent solution to 02 percent solution?
add 4 parts water per part solution
How much water must be added to 300 liters of a solution so that its concentration change from 25 percent to 20 percent?
Well, isn't that a lovely little problem to solve? To decrease the concentration from 25% to 20%, we need to dilute the solution. Since the concentration is decreasing by 5%, we can calculate that we need to add 60 liters of water to the 300 liters of solution to achieve the desired concentration of 20%. Just like painting, a little change can make a big difference in creating the perfect mixture.
There were 2 liters of water in a bottle. 500 ml evaporated. What percent of the water evaporated?
25%
How many liters of pure water must be evaporated from 60 liter of a 3 percent salt water solution to produce a solution that will be a 5 percent salt water solution?
Well, it's been awhile since I've done this but my answer would be 24 liters must evaporate to make a 5% solution. 60 * .03 = 1.8 ~ That's what you have. The 1.8 is how many liters of salt you have. 60 = x ~ Replace 60 with x. x * .05 = 1.8 ~ The percentage of salt is now 5 but you still have 1.8 liters. 1.8/.05=36 ~ algebra... 60 - 36 = 24 ~ Total minus how much will remain gives you the total that must evaporate. I know you could have followed them easily enough without the notes. They were more for me so I knew I'd done it correctly. :-) Hope it's right and .
How much pure water must be mixed with 10 liters of a 25 percent acid solution to reduce it to a 10 percent acid solution?
To reduce a 25% acid solution to 10%, the water needed can be calculated using the formula: (10 x (25-10))/(10) = 1.5 liters. So, 1.5 liters of pure water must be mixed with the 10 liters of 25% acid solution to reduce it to 10%.
How can i make a 10 percent glucose solution from 50 percent glucose solution?
Let's say the total solution is 100 liters. 50 of the liters is glucose and 50 is water. We want to make the 50 glucose equal to 10% of the total solution. For that to happen, we need to make the total solution 500 liters (50 of the 500 would be a 10% solution). So we add 400 liters of water to the original 100 liter (50/50) solution. Take the total number of units and multiply by 4. Add that much in water.
Determine the strength of a polymer solution as a percent if 80 grams of polymer are mixed with 16 liters of water?
0.1125% of polymer solution.
How many liters to 50 percent water and 50 percent of hydrogen peroxide?
If you have a solution that is 50% water and 50% hydrogen peroxide, you would have equal volumes of each component. So if you have 1 liter of this solution, you would have 0.5 liters of water and 0.5 liters of hydrogen peroxide.
How many liters of water must be added to 7 liters of a 20 percent acid solution to obtain a 10 percent acid solution?
7 liters of a 20% acid solution consists of 1.4 liters of acid (20% of the total volume) mixed with 5.6 liters of water (80% of the total volume). The amount of acid isn't going to change in the new solution. You are just going to add enough water to make it a 10% solution instead of a 20% solution. So it will be more dilute. That means that 1.4 liters of acid will represent 1/10 of the volume of the new solution. So the total volume of the new solution will be 10 x 1.4 or 14 liters. The amount of water in the new solution will be 14 - 1.4 = 12.6 liters. That is a difference of 12.6 - 5.6 = 7 liters from the amount of water you started with. So you need to add 7 liters of water to the original 20% solution to make it a 10% solution. This makes sense because if you double the amount of the mixture from 7 liters to 14 liters and the amount of acid is unchanged, the solution will be half as strong.
How do you make a 50 percent solution?
You take y liters of the solution and put it into a bucket or container. You then put y (same amount as before) liters of water in the same container, and voila! You now have a container with 50 percentile solution, 50 percentile water.
Jorge has four liters of 30 percent acid solution how much water should he add to make 25 percent acid solution'?
Jorge needs to add 2 liters of water to the 30% acid solution to make a 25% acid solution. This can be calculated using a dilution formula: initial acid amount / final total amount = final acid concentration.
In order to get 10 percent HCl how much liters of water is needed when combined with 0 Celsius degrees 0.7 atmosphere pressure and 160 liters of HCl and The answer is 1.64l so how do u solve it?
In order to get 10 percent HCl how much liters of water is needed when combined with 0 Celsius degrees 0.7 atmosphere pressure and 160 liters of HCl it will take a lot of thinking. The answer to this question is 1.64L.
How many liters of water must be added to 30 liters of 20 percent ALCOHOL solution to dilute it to a15 percent solution?
You have 6 litres of alcohol in 24 litres of water You need to add x litres to make 6 equal to 15% of 30 + x. 6 is 15% of 40, so x = 10
A chemist wants to make a 10 solution of fertilizer. how much water and how much of a 30 solution should the chemist mix to get 30 L of a 10 solution?
30 liters of a 10 % solution of fertilizer has .1(30) = 3 liters of fertilizer 1 liter of 30% solution has .3 liter of fertilizer 10 liters of 30% solution has 3 liters of fertilizer so, the chemist needs 10 liters of the 30% solution and 20 liters of water to make 30 liters of a 10% solution.
How many ml of 50 percent dextrose solution and how many ml of water are needed to prepare 4.5 L of a 1 percent solution?
90 ml of dextrose and 4.41 litres of water.
How much water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution?
To make a 2% solution from a 25% solution, you need to dilute it. Let x ml be the amount of water needed. Using the equation for mass balance: 0.25(40) = 0.02(40 + x), solve for x to find that x = 875 ml of water needs to be added.
