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Q: A radioisotope has a half-life of 6.0 hours What fraction of the original mass will remain after 12.0 hours?

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The remainder is 2-p or 0.5p of the original amount.

The answer depends on 3240 WHAT: seconds, days, years?

by multiplying the denominator with the whole number and adding the numerator. the denominator will remain the same.

Approx 6.1% remains.

This is true; if you multiply both numbers by the same number, the proportion will remain the same.

Related questions

The remainder is 2-p or 0.5p of the original amount.

After each half-life, half of the radium-226 will decay. Therefore, after four half-lives, 1/2^4 or 1/16th of the original gram of radium-226 will remain unchanged. This means that 1/16th of a gram, or 0.0625 grams, will still be unchanged after four half-lives.

176

This depends on this specific half life and the intial amount of sample.

original remain is organisms encased in amber and i dont know if you can find it in tar

how important is for a film maker to remain true to the original story

Approx 1/8 will remain.

how important is for a film maker to remain true to the original story

Yes they do .I have seen one

The answer depends on 3240 WHAT: seconds, days, years?

only if it is moved parallel to its original direction

The half-life of C14 is 5730 years so the given period is 5 half-lives. You should, therefore, expect approx 2-5 = 0.03125 of the original C14 to remain.