Roughly a third.
1g (1/2)4 = 1/16 g
Age = no. of half lives x duration of each half life ratio of Parent nuclei : Daughter Nuclei 1 : 15 total of 16 parts, and for every 16 parts one part is a parent nuclei Mt = Mo x (0.5)^n Mt = amount remaining Mo = Initial amount n = number of 1/2 lives Mt = 1/16 (1/2)^n = 1/16 (1/2)^n = (1/2)^4 n=4 Age = 4 x duration of each half life Age = 4 x 300 Age = 1200 Therefore, the age of the specimen is 1200 years.
The answer depends on the total number of students at the school. Since this information has not been disclosed, it is not possible to answer the question.
There is no such word.An integrator is a person or operation that integrates a function.
Approx 1/8 will remain.
12.5%
Not sure what you mean by "had-lives". After 3 half lives, approx 1/8 would remain.
Massive nuclei are unable to remain bound aganst the repulsive force of their protons, which all have positive charge. This also occurs with elements #43 (technetium) and #61 (promethium) which because of their particular nuclear geometry are inherently unstable and radioactive, with the only natural isotopes having half-lives of just over 2 years.
After seven half lives, approximately 0.78125% (1/2^7) of the original radioactive element will remain. This can be calculated by repeatedly halving the remaining amount after each half life.
1/8 of the original amount remains.
12.5%
After three half-lives, only 1/8 (or 12.5%) of the original radioactive sample remains. This is because each half-life reduces the amount of radioactive material by half, so after three half-lives, you would have (1/2) * (1/2) * (1/2) = 1/8 of the original sample remaining.
It depends on the half-life of the radioactive element. After one billion years, only a fraction of the original amount would remain, based on the decay rate determined by the half-life of the element.
After 5 half-lives, 3.125% (or 1/2^5) of a radioactive sample remains. Each half-life reduces the sample by half, so after 5 half-lives, there is only a small fraction of the original sample remaining.
Only 1/32 of the original radioactive material will remain. (½)5 = 1/32
If I take a radioactive sample of 400 moles of an unknown substance and let it decay to the point of three half-lives I would have 50 moles left of the sample. 1/2 of what is left will decay in the next half-life. At the end of that half-life I will have 25 moles left of the unknown substance or 4/25.