The remainder is 2-p or 0.5p of the original amount.
Roughly a third.
1g (1/2)4 = 1/16 g
Age = no. of half lives x duration of each half life ratio of Parent nuclei : Daughter Nuclei 1 : 15 total of 16 parts, and for every 16 parts one part is a parent nuclei Mt = Mo x (0.5)^n Mt = amount remaining Mo = Initial amount n = number of 1/2 lives Mt = 1/16 (1/2)^n = 1/16 (1/2)^n = (1/2)^4 n=4 Age = 4 x duration of each half life Age = 4 x 300 Age = 1200 Therefore, the age of the specimen is 1200 years.
Cobalt-60 has a half-life of approximately 5.27 years, meaning that after this period, half of the original amount will have decayed. After 14 years, which is about 2.65 half-lives, the remaining amount can be calculated using the formula: remaining amount = original amount × (1/2)^(time/half-life). Therefore, after 14 years, approximately 1/6 of the original amount of cobalt-60 will remain.
The answer depends on the total number of students at the school. Since this information has not been disclosed, it is not possible to answer the question.
Approx 1/8 will remain.
12.5%
Not sure what you mean by "had-lives". After 3 half lives, approx 1/8 would remain.
Massive nuclei are unable to remain bound aganst the repulsive force of their protons, which all have positive charge. This also occurs with elements #43 (technetium) and #61 (promethium) which because of their particular nuclear geometry are inherently unstable and radioactive, with the only natural isotopes having half-lives of just over 2 years.
1/8 of the original amount remains.
After seven half lives, approximately 0.78125% (1/2^7) of the original radioactive element will remain. This can be calculated by repeatedly halving the remaining amount after each half life.
12.5%
After three half-lives, only 1/8 (or 12.5%) of the original radioactive sample remains. This is because each half-life reduces the amount of radioactive material by half, so after three half-lives, you would have (1/2) * (1/2) * (1/2) = 1/8 of the original sample remaining.
That depends on the "half-life" of that particular radioactive element, which the question forgot to state. They're all different. Various radioactive elements have half-lives ranging from microseconds to millions of years.
After 5 half-lives, 3.125% (or 1/2^5) of a radioactive sample remains. Each half-life reduces the sample by half, so after 5 half-lives, there is only a small fraction of the original sample remaining.
Only 1/32 of the original radioactive material will remain. (½)5 = 1/32
If I take a radioactive sample of 400 moles of an unknown substance and let it decay to the point of three half-lives I would have 50 moles left of the sample. 1/2 of what is left will decay in the next half-life. At the end of that half-life I will have 25 moles left of the unknown substance or 4/25.