1/4
The remainder is 2-p or 0.5p of the original amount.
The answer depends on 3240 WHAT: seconds, days, years?
Approx 6.1% remains.
by multiplying the denominator with the whole number and adding the numerator. the denominator will remain the same.
This is true; if you multiply both numbers by the same number, the proportion will remain the same.
The remainder is 2-p or 0.5p of the original amount.
After each half-life, half of the radium-226 will decay. Therefore, after four half-lives, 1/2^4 or 1/16th of the original gram of radium-226 will remain unchanged. This means that 1/16th of a gram, or 0.0625 grams, will still be unchanged after four half-lives.
176
This depends on this specific half life and the intial amount of sample.
Approximately 25% of Carbon 14 would remain in charcoal burned in a primitive man's campfire after about 28,000 years. This is because Carbon 14 has a half-life of around 5,730 years, so after multiple half-lives, only a fraction of the original amount will remain.
The rock is approximately 3.2 million years old. This can be calculated by dividing the half-life of the radioisotope (400,000 years) by the time it takes for 6.25 percent of it to remain (0.0625), which gives us 6 half-lives. Multiplying 400,000 by 6 gives us 2.4 million years, and since we need to account for the original amount as well, the total age of the rock is 3.2 million years.
original remain is organisms encased in amber and i dont know if you can find it in tar
how important is for a film maker to remain true to the original story
Approx 1/8 will remain.
how important is for a film maker to remain true to the original story
Yes they do .I have seen one
The answer depends on 3240 WHAT: seconds, days, years?