a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?
It is: 12 units in length
Length = 3.5 inches and Width = 2.5 inches Check: 2(3.5+2.5) = 12 inches
First find the dimensions of the rectangle. Let the length be x+4 and the width be x: 2(x+4+x) = 20 2x+8+2x = 20 4x = 20-8 4x = 12 => x = 3 Therefore: length = 7cm and the width = 3cm Area = length*width => 21cm2
the width equals 14 cm. and the length equals 31 cm.
a rectangle as a longer side because there's 48 inches for a rectangle but there's only 45 inches for a triangle. a rectangle as a longer side because there's 48 inches for a rectangle but there's only 45 inches for a triangle.
The dimensions are: length 10.5 cm and width 3.5 cm Check: 2*(10.5+3.5) = 28 cm
It is: 12 units in length
Length = 3.5 inches and Width = 2.5 inches Check: 2(3.5+2.5) = 12 inches
i don't know what length of rectangle is 7 cm longer than the width the perimeter of the rectangle is 46 cm .what is the length of the of the rectangle ?
21cm3
L + W >= 24, L = W + 4, Possible dimensions 14 and 10 giving an area of 140 sq cm.
perimeter = 2(length X width) = 2(l x w) = 2(w+7+w) - 2(2w+7)=142 2w+7 = 71; 2w=64; w = 32 and l = w+7 = 39 Check: perimeter = 2(32+37) = 142
Perimeter of a rectangle is 2(l+b).Area of rectangle is 216 centimeter square.
17 and 22
not really but the length is always the longer side :)
First find the dimensions of the rectangle. Let the length be x+4 and the width be x: 2(x+4+x) = 20 2x+8+2x = 20 4x = 20-8 4x = 12 => x = 3 Therefore: length = 7cm and the width = 3cm Area = length*width => 21cm2
the width equals 14 cm. and the length equals 31 cm.