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It is: 12 units in length

Q: The perimeter of a rectangle is 36 and its area is 72 What is the length of the rectangle's longer side?

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a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?

the width equals 14 cm. and the length equals 31 cm.

a rectangle as a longer side because there's 48 inches for a rectangle but there's only 45 inches for a triangle. a rectangle as a longer side because there's 48 inches for a rectangle but there's only 45 inches for a triangle.

Yes, there is. The area of a rectangle sets a lower limit on its perimeter.If the area is A, then the quadrilateral shape with the smallest perimeter has sides of length sqrt(A). Therefore the minimum perimeter is 4*sqrt(A). The perimeter can have any value grater than that since the area of the rectangle can be maintained while making it thinner and longer and thus increasing its perimeter with out any upper limit.

4

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a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?

i don't know what length of rectangle is 7 cm longer than the width the perimeter of the rectangle is 46 cm .what is the length of the of the rectangle ?

21cm3

Perimeter of a rectangle is 2(l+b).Area of rectangle is 216 centimeter square.

All squares are rectangles, but not all rectangles are squares. Basically, a square is a rectangle where all sides are the same length. However, providing that the width is half of the length, or vice versa, and you join the two rectangles along the one of the sides that is longer, two rectangles can make a square. Example: 1x2 rectangle joined with another 1x2 rectangle will make a 2x2 square.

the width equals 14 cm. and the length equals 31 cm.

Perimeter is a length, and a length cannot be the same as an area.Ignoring the units, all rectangles that have the same numerical perimeter as area are those that satisfy:2 x (length + width) = length x widthwhich can be rearranged to give:width = 2 x length/(length - 2)Meaning that given any length over 2, a width can be found to give a rectangle that meets the requirement that its numerical perimeter is the same as its numerical area. (For a length greater than 0 and less than 2, the width would be negative and not possible; similarly for a length less than 0, the length is negative and not possible. When the length is 2, the width is undefined and so not possible. When the length is 0 the width is 0 and it is not a rectangle.)At some stage as the length increases, the length will equal the width and as the length continues to increase the rectangle then given will match the previous rectangles with the length and widths swapped. This occurs when:length = 2 x length/(length - 2)â‡’ length x (length - 4) = 0â‡’ length = 4.So, as long as the length is greater than or equal 4 it will be the longer side - the length, by convention, is the longer side. Thus all rectangles satisfy:width = 2 x length/(length - 2)with length â‰¥ 4, will have the numerical value of their perimeter the same as the numerical value of their area.For example:4 cm x 4 cm: perimeter = 16 cm, area = 16 cm25 cm x 31/3 cm: perimeter = 162/3 cm, area = 162/3 cm26 cm x 3 cm: perimeter = 18 cm, area = 18 cm241/2 cm x 33/5 cm: perimeter = 161/5 cm, area = 161/5 cm2etcNote: the first example is a square which is a rectangle with all the sides the same length.

Assuming that this is a rectangle, you know that the length (longer side) would be 7cm, and the width (shorter side) would be 6cm. The formula for perimeter is, 2(length) + 2(width) = Perimeter Now we can plug in our numbers, 2(7cm) + 2(6cm) = 14cm + 12cm = 26cm The perimeter would be 26cm, assuming that this is a rectangle ^^

A rectangle with a perimeter of 48 and 1 side equal to 5 would have its other sides lengths of 5, 19, 19. Such a rectangle would have an area of 95 sq/m. Your question is somewhat strange, as the "length" of a rectangle generally refers to the longer side - in this case the length would be 19 and the width 5.

shorter side = 10 longer side = 19

Length is 11 and width is 7 and so 11 times 7 = 77 square cm

If the rectangle is 12 feet long and has a perimeter of 40, then the height must be 8. If it is made 6 feet longer, it will have a length of 18 and a height of 8. The new area will be 144.