124=4wxw
124/4=4w2/4
31=w2
5.56=w
L=22.4
W=5.6
South Dakota.----Many have a rough shape of a rectangle, but Wyoming and Colorado seem to be nearest to a true rectangle.
As far as I can see I would say exactly zero.
The area of the WHOLE rectangle is less than 0.01 sq metres. So it is a lot less than a cent (which is 40 metres2 ). So to the nearest tenth of a cent, the area of the circle, which will be smaller than that of the rectangle, is 0. No calculations required.
Use Pythagoras' theorem: 1272+76.22 = 21935.44 and the square root of this is 148.1061781 Answer: 148 to the nearest cm
I can and will. So if you put the diagonal through a rectangle you create a right angled triangle of which you can use pythagoras theorem. x2 = 152 + 62 x2= 261 x = 16.16m
South Dakota.----Many have a rough shape of a rectangle, but Wyoming and Colorado seem to be nearest to a true rectangle.
South Dakota.----Many have a rough shape of a rectangle, but Wyoming and Colorado seem to be nearest to a true rectangle.
15 (it is actually really close to 15 and a half)
As far as I can see I would say exactly zero.
It could be any value in the range (2.65, 2.75) square units.
The area of the WHOLE rectangle is less than 0.01 sq metres. So it is a lot less than a cent (which is 40 metres2 ). So to the nearest tenth of a cent, the area of the circle, which will be smaller than that of the rectangle, is 0. No calculations required.
Use Pythagoras' theorem: 1272+76.22 = 21935.44 and the square root of this is 148.1061781 Answer: 148 to the nearest cm
I can and will. So if you put the diagonal through a rectangle you create a right angled triangle of which you can use pythagoras theorem. x2 = 152 + 62 x2= 261 x = 16.16m
Suppose you had a rectangle that was 12.75 units by 19.6 units. The area would be 249.9 square units which would round to 250 square units to the nearest square unit. Since a centimeter isn't a square unit, it can't be rounded to the nearest square unit.
Use the Law of Pythagoras - in this case, the answer is the square root of (162 + 92).
Draw a diagonal line across the rectangle. The resulting two right triangles will each have identical areas half that of the rectangle. The area of the rectangle is its height x base, and the area of each of the two triangles is 1/2 of its height x base.
The flag is divided horizontally into a red (top) and blue (bottom) rectangle. From the side nearest the flagpole - extends a white equilateral triangle containing a gold 1 large, and 3 small stars.