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A stone is thrown vertically upward with a speed of 12 meters per second from the edge of a 70 m cliff How much later does it reach the bottom of the cliff?
Wiki User
∙ 12y ago
H = H0 + V0 T + 1/2 G T2
H0 = 70 m
V0 = 12 m/s
G = -9.8 m/s2
We want to know ' T ' when H=0 .
0 = 70 + 12 T - 4.9 T2
Quadratic formula:
T = -1/9.8 [ -12 ± sqrt(144 + 1,372) ] =
-1/9.8 [ -12 ± 38.9358 ] =
T = 5.1975 seconds(T = -2.7486 seconds is also a solution to the math but isn't physically relevant)
Wiki User
∙ 12y ago
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