1000000 m
We have no idea how big the rock is, and no way to figure it out. But we can calculate that it reaches 11.48 meters above the ground before it starts falling.
They should reach the ground together, since their initial vertical speed is the same, namely zero.
The height, in feet, above the ground at time t, H(t) = 40 + 32*t - 16*t2
At the time the ball is thrown, which is "time 0" the downward speed is 40 m/s.Each second, the downward speed will increase by 9.8 m/s.1. Work out the speed at the end of the first second. This will be 49.8 m/s.2. Then work out how many meters it would have gone in the first second.3. Now work out the ball's height. This is the height at "time 1".4. Draw the ball at time 0 and time 1 on a sheet of paper to help you think.Now, repeat steps 1-4 until the ball's height is close to 0 or goes past 0. Your current "time X" will tell you how many seconds went by for it to get that far.
The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.
17.8 meters
It depends on the height of the building and also on the direction the object is thrown in (up, down etc.).
swagger
We have no idea how big the rock is, and no way to figure it out. But we can calculate that it reaches 11.48 meters above the ground before it starts falling.
Zero meters
They should reach the ground together, since their initial vertical speed is the same, namely zero.
6.261 m/s
The height, in feet, above the ground at time t, H(t) = 40 + 32*t - 16*t2
An object thrown vertically up wards from the ground returned back to the ground in 6s after it was thown up if it reached a height of 12m calculate?
The answer depends on whether the ball is thrown vertically upwards or downwards. That critical piece of information is not provided!
At the time the ball is thrown, which is "time 0" the downward speed is 40 m/s.Each second, the downward speed will increase by 9.8 m/s.1. Work out the speed at the end of the first second. This will be 49.8 m/s.2. Then work out how many meters it would have gone in the first second.3. Now work out the ball's height. This is the height at "time 1".4. Draw the ball at time 0 and time 1 on a sheet of paper to help you think.Now, repeat steps 1-4 until the ball's height is close to 0 or goes past 0. Your current "time X" will tell you how many seconds went by for it to get that far.
The ball was thrown horizontally at 10 meters per sec, and the thrower's arm was 78.4 meters above the base of the cliff.