Q: A student had a 100 coins total 7.00 He had no nickels what coins did he have if 60 percent of coins are of one kind?

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Tjats a pretty simple question. Anthony has. 2 pennies, 4 dimes, and 4 nickels

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10 Nickels 2 Quarters = $1.00 4 Dimes 7 Nickels 1 Quarter = $1.00 8 Dimes 4 Nickels = $1.00

The coins in the store's cash register total $12.50. The cash register contains only nickels, dimes, and quarters. There are twice as many dimes as nickels. There are also twice as many quarters as dimes. How many quarters are in the cash register?

One solution is 10 nickels, because if you put in a dollar it can be broken into: 2 quarters (50 cents) so 50 cents are left, and you have 10 coins left to use If these 10 coins are all nickels, (total: 50 cents), the problem is solved! .5 +.5 =1 dollar

If n is the number of nickels and d the number of dimes, then the equations are:n + d = 160 (total number of coins) 5n + 10d = 1050 (total value). And I have thought through to the answer.

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Three of the 6 coins had to be nickels. The six coins are 1 quarter, 1 dime, 3 nickels, and 1 penny.

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Using pennies, nickels, and dimes: 85 pennies 1 nickel 1 dime Total = 87 coins.