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An automobile with initial speed 4 point 15 m per s accelerates uniformly at 2 point 7 m per s 2 and after 4 point 8 s the final speed is 17 point 11 m per s what is the displacement after 4 point 8 s?
Wiki User
∙ 13y ago
Since the car accelerates uniformly, its average speed during the interval is
1/2 (initial speed + final speed) = 1/2 (4.15 + 17.11) = 10.63 m/s.
The distance covered is (average speed) x (time) = (10.63) x (4.8) = 51.024 meters.
If the motion during the 4.8 seconds was all in the same direction along a straight line,
then that same 51.024 meters is also the displacement during that time.
If, instead, it happened to take 4.8 seconds to go around a circle with a circumference
of 51.024 m, then the displacement over the 4.8 seconds is zero, since the starting line
is also the finish line.
Wiki User
∙ 13y ago
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How do you determine initial velocity when given time acceleration and displacement?
s = u + at s = displacement u = initial velocity a = acceleration t = time rearrange to give u = s - at and sub in values
How does the total time changes as the total distance increases in case of uniformly accelerated motio n?
the formula that ties displacement (you can think of it as distance in a given direction), velocity, time and acceleration (a) is : s = s0+vt + 1/2at^2 s0 = initial displacement (you can equate to 0, if you start at 0) vt = starting velocity times time (you can equate to 0 if initial velocity is 0) s= final displacement so s=1/2at^2 = (1/2 x a x t x t), so here you end up with a relationship between displacement, acceleration and time. (note: ^2 stands for "to the 2nd power")
What is the formula for calculating displacement in which initial velocity and time are the variables?
If the velocity is constant, thenDisplacement = (initial velocity) multiplied by (time)
What affects a pendulum?
The mass of the pendulum, the length of string, and the initial displacement from the rest position.
True or false To calculate the acceleration of and automobile you must first subtract the final speed from the initial speed?
True
Why is displacement of displacement?
The difference between the final and the initial position of an object is called displacement. Unit of displacement is metre . Displacement <= Distance always.
What is the name of the length of the straight line that is drawn form an objects initial position and to the object's final position?
Displacement
How to find displacement?
Final position - Initial position
How do you find displacement when you only have acceleration initial velocity and final velocity?
Kinematics. Final velocity squared = initial velocity squared + 2(gravitational acceleration)(displacement)
What is describe velocity?
velocity is displacement / time. Displacement is shortest distance between initial and final point
How can we calculate the magnitude of displacement?
The magnitude of displacement is the shortest distance between the initial and final position. In case of a particle completing one full round around a circle the displacement is ZERO. Because the initial and final positions are one and the same
If the initial displacement from equilibrium amplitude is changed does the period of oscillation change?
Initial displacement has no effect on the period of oscillation. The period T = 2(pi)sqrt(mass/spring constant)
What is the displacement of satellite when it completes a round along its circular path explain?
displacement is 0 because the initial position is same.
How do you determine initial velocity when given time acceleration and displacement?
s = u + at s = displacement u = initial velocity a = acceleration t = time rearrange to give u = s - at and sub in values
How does the total time changes as the total distance increases in case of uniformly accelerated motio n?
the formula that ties displacement (you can think of it as distance in a given direction), velocity, time and acceleration (a) is : s = s0+vt + 1/2at^2 s0 = initial displacement (you can equate to 0, if you start at 0) vt = starting velocity times time (you can equate to 0 if initial velocity is 0) s= final displacement so s=1/2at^2 = (1/2 x a x t x t), so here you end up with a relationship between displacement, acceleration and time. (note: ^2 stands for "to the 2nd power")
Give an example where displacement is zero but distance is not?
when the body moves circularly from a point 'A' to a then the displacement will be zero(displacement is the shortest diatance from the initial point to final point) and the distance will not be zero.
What is the formula for calculating displacement in which initial velocity and time are the variables?
If the velocity is constant, thenDisplacement = (initial velocity) multiplied by (time)
