0
Add your answer:
Earn +20 pts
What are two ways of adding together 19 49 and 99 using Roman numerals throughout both calculations?
19 = XIX 49 = XLIX 99 = XCIX Expected result is 167 = CLXVII Method 1: Convert subtractive pairs so IV becomes IIII, XL becomes XXXX and XC becomes LXXXX. Then sort values in descending order of value, grouping C, X and I in groups of 5, and L and V in groups of 2, then reduce these groups so that IIIII becomes V, VV becomes X, XXXXX becomes L and LL becomes C. XIX + XLIX + XCIX = XVIIII + XXXXVIIII + LXXXXVIIII = L + XXXXX + XXXX + VV + V + IIIII + IIIII + II = L + XXXXX + XXXX + VV + VV + V + II = L + XXXXX + XXXXX + X + V + II = LL + L + X + V + II = C + L + X + V + II = CLXVII Method 2: Expand all symbols into positive and negative symbols, sort by absolute value, cancel out any similar values with opposing signs. Convert higher values to lower values as required. XIX + XLIX + XCIX = X - I + X - X + L - I + X - X + C - I + X = C + L + X + X - X + X - X + X - I - I - I = C + L + X + X - I - I - I = C + L + X + V + V - I - I - I = C + L + X + V + I + I + I + I + I - I - I - I = C + L + X + V + I + I = CLXVII
What did the letters v x m l c and you stand for in ancient roman?
v = 5 x = 10 m = 1000 L = 50 C = 100
A list of Roman Numerals?
They are: M=1000, D=500, C=100, L=50, X=10, V=5 and I=1 Note: 5*I=V, 2*V=X, 5*X=L, 2*L=C, 5*C=500 and 2*D=1000
How many times can the roman numeral be repeated?
In traditional Roman numerals, each symbol can be repeated up to three times in a row. For example, III represents the number 3. However, there are alternative forms of Roman numerals that allow for larger repetitions, but these are not commonly used.
How do you write '248' in Roman Numerals?
C c x l v i i i
See roman numerals of 135 120 200 70 190 65?
135 = c x x x v120 = c x x200 = c c70 = L x x190 = c x c65 = L x v
Roman number symbols?
8 january 2013Improved Answer:-The main symbols are: M=1000, D=500, C=100, L=50, X=10, V=5 and I=1Note that: 5*I=V, 2*V=X, 5*X=L, 2*L=C, 5*C=D and 2*D=M
What do you get if you divide c by x and then divide result by v?
(c/x) /v = (c/x) * (1/v) = c/(x*v), so c divided by (the product of x and v).
How would you actually find the sum of 1492 14 and 49 in two different ways using only Roman numerals in step by step stages throughout both calculations giving reasons why?
1492 = MCDXCII14 = XIV49 = XLIXSum: 1492 + 14 + 49 = MCDXCII + XIV + XLIXExpected answer: 1555 = MDLVMethod 1Similar to the decimal system. Work from the right and examine the unit portions of each value. Expand the individual values, cancel out the positive and negative values and sum the remainder. If the result is greater than or equal to X, carry the X(s) and leave the remainder (the units). Repeat for the tens portion, the hundreds and the thousands. Combine the answers.Start with the units:II + IV + IX =I + I - I + V - I + X = (expanded)I + I - I + V - I + X = (cancel out similar + and - values)V + X =XV =V (carry X)Now the tens (with carry):XC + X + XL ( + X) =- X + C + X - X + L + X = (expanded)- X + C + X - X + L + X = (cancel out similar + and - values)C + L =CL =L (carry C)And the hundreds (with carry):CD ( + C ) =- C + D + C = (expanded)- C + D + C = (cancel out similar + and - values)D (no carry)And finally the thousands (no carry):MCombine the results:M + D + L + V =MDLVMethod 2Combine the numbers into a single number and expand the individual values. Cancel all similar positive and negative values. Then sort in descending order. Simplify if necessary.MCDXCII + XIV + XLIX =MCDXCIIXIVXLIX = (combined)M - C + D - X + C + I + I + X - I + V - X + L - I + X = (expanded)M - C + D - X + C + I + I + X - I + V - X + L - I + X = (cancel out similar + and - values)M + D + V + L = (unsorted)M + D + L + V = (sorted)MDLV
If V is 5 what is c?
I = 1, V = 5, X = 10, L = 50, C = 100, D = 500 and M = 1000.
How did the Romans teach math?
They used letters instead of the numbers that we use today and these letters had the following values:- M=1000, D=500, C=100, L=50, X=10, V=5 and I=1 5*I=V, 2*V=X, 5*X=L, 2*L=C, 5*C=D and 2*D=M
What do the letters C D L M V X have in common?
roman numerals
