No, it cannot.
The radius of the circle that is perpendicular to a chord intersects the chord at its midpoint, so it is said to bisect the chord.
Only when one of them is the circle's diameter which is the circle's largest chord.
A circle cannot form a perpendicular bisector.
If two chords of a circle bisect each other, they must intersect at a point that is equidistant from both endpoints of each chord. By the properties of circles, the perpendicular bisector of any chord passes through the center of the circle. Since the two chords bisect each other at the same point and are both perpendicular to the line connecting their endpoints, this point must also be the center of the circle, making both chords diameters of the circle. Thus, if two chords bisect each other, they are indeed diameters of the circle.
A circle cannot form a perpendicular bisector.
Only if the parallelogram is in the form of a rhombus will its diagonals bisect each other at right angles
Yes. it is possible to bisect a segment with a perpendicular segment. Follow the link to learn how to do it: http://www.mathopenref.com/constbisectline.html
Easy if you know how to draw a perpendicular and to bisect angles. Draw a perpendicular = 90 degrees. Bisect it = 45 degrees Bisect that = 22.5 degrees. Not sure how you can do it without that knowledge.
A circle itself does not form a perpendicular bisector because a perpendicular bisector is a line that divides a segment into two equal parts at a right angle, typically associated with straight segments. However, the concept of a perpendicular bisector can be applied to chords within a circle. The perpendicular bisector of a chord will always pass through the center of the circle.
Perpendicular bisector lines intersect at right angles
yes
perpendicular and bisect each other