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The radius of the circle that is perpendicular to a chord intersects the chord at its midpoint, so it is said to bisect the chord.

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If a radius of a circle is perpendicular to a chord then?

Then the radius bisects the chord.


If a radius of a circle intersects a chord then it bisects that chord?

If radius of a circle intersects a chord then it bisects the chord only if radius is perpendicular to the chord.


If a radius of a circle is perpendicular to a chord then it that chord?

Bisects


If a radius of a circle bisects a chord then it is to that chord?

Perpendicular.


A radius of a circle is perpendicular to a chord if and only if?

Bisects that chord


If a radius of a circle intersects a chord it is perpendicular to that chord?

False


What is a line perpendicular to a radius of a circle called?

A Chord. Or another radius!


True or False If a radius of a circle intersects a chord it is perpendicular to that chord?

its false


If a radius of a circle is perpendicular to a chord then it bisects that chord?

YesAt a right angle


In a circle the perpendicular bisector of a chord must pass through the center of the circle?

Yes, in a circle, the perpendicular bisector of a chord does indeed pass through the center of the circle. This is because the perpendicular bisector of a chord divides it into two equal segments and is equidistant from the endpoints of the chord. Since the center of the circle is the point that is equidistant from all points on the circle, it must lie on the perpendicular bisector. Thus, any chord's perpendicular bisector will always intersect the center of the circle.


True or False if a radius of a circle is perpendicular to a chord then it bisects that chord?

true, because both distances of the chord are congruent


The point of concurrency for perpendicular bisectors of any triangle is the center of a circumscribed circle true or false?

The perpendicular bisector of ANY chord of the circle goes through the center. Each side of a triangle mentioned would be a chord of the circle therefore it is true that the perpendicular bisectors of each side intersect at the center.