The radius of the circle that is perpendicular to a chord intersects the chord at its midpoint, so it is said to bisect the chord.
If radius of a circle intersects a chord then it bisects the chord only if radius is perpendicular to the chord.
true, because both distances of the chord are congruent
The relationship between the chord and the radius of the circle is Length of the chord = 2r sin(c/2) where r = radius of the circle and c = angle subtended at the center by the chord
False
Radius
Then the radius bisects the chord.
Bisects
Perpendicular.
If radius of a circle intersects a chord then it bisects the chord only if radius is perpendicular to the chord.
Bisects that chord
False
A Chord. Or another radius!
its false
YesAt a right angle
true, because both distances of the chord are congruent
The perpendicular bisector of ANY chord of the circle goes through the center. Each side of a triangle mentioned would be a chord of the circle therefore it is true that the perpendicular bisectors of each side intersect at the center.
-- Draw any two random chords of the circle. -- Construct the perpendicular bisector of each chord. -- The perpendicular bisectors intersect at the center of the circle. All of this can be done with a compass, an unmarked straight-edge, and a pencil.