The radius of the circle that is perpendicular to a chord intersects the chord at its midpoint, so it is said to bisect the chord.
If radius of a circle intersects a chord then it bisects the chord only if radius is perpendicular to the chord.
true, because both distances of the chord are congruent
The relationship between the chord and the radius of the circle is Length of the chord = 2r sin(c/2) where r = radius of the circle and c = angle subtended at the center by the chord
False
A part of a circle is called an arc. The defined values for a circle are: radius, diameter, chord, area, circumference, and the arcs. There is the circumfrence, semi circle, arc, diameter,chord,segment,radius,quaderent
Then the radius bisects the chord.
If radius of a circle intersects a chord then it bisects the chord only if radius is perpendicular to the chord.
Bisects
Perpendicular.
Bisects that chord
False
A Chord. Or another radius!
its false
YesAt a right angle
Yes, in a circle, the perpendicular bisector of a chord does indeed pass through the center of the circle. This is because the perpendicular bisector of a chord divides it into two equal segments and is equidistant from the endpoints of the chord. Since the center of the circle is the point that is equidistant from all points on the circle, it must lie on the perpendicular bisector. Thus, any chord's perpendicular bisector will always intersect the center of the circle.
true, because both distances of the chord are congruent
The perpendicular bisector of ANY chord of the circle goes through the center. Each side of a triangle mentioned would be a chord of the circle therefore it is true that the perpendicular bisectors of each side intersect at the center.