Yes. When all vectors point in the same direction the inequality rule is applied and r can be less than r1 + r2.
For a start, you can't compare a vector with a scalar, so you can't really compare a vector with its magnitude, either. To say which is larger, you can't even compare one vector with another - you can only compare their magnitudes.
If the scalar is > 1 the resultant vector will be larger and in the same direction. = 1 the resultant vector will be the same as the original vector. between 0 and 1 the resultant vector will be smaller and in the same direction. = 0 the resultant vector will be null. If the scalar is less than 0, then the pattern will be the same as above except that the direction of the resultant will be reversed.
No a vector may not have a component greater than its magnitude. When dealing with highschool phyics problems, the magnitude is usually the sum of two or more components and one component will offset the other, causing the magnitude to be less then its component
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The resultant vector IS the sum of the individual vectors. Its magnitudecan be the sum of their individual magnitudes or less, but not greater.
For a start, you can't compare a vector with a scalar, so you can't really compare a vector with its magnitude, either. To say which is larger, you can't even compare one vector with another - you can only compare their magnitudes.
If the scalar is > 1 the resultant vector will be larger and in the same direction. = 1 the resultant vector will be the same as the original vector. between 0 and 1 the resultant vector will be smaller and in the same direction. = 0 the resultant vector will be null. If the scalar is less than 0, then the pattern will be the same as above except that the direction of the resultant will be reversed.
A magnitude of less than 1. cw: An absolute magnitude of less than 1.
No a vector may not have a component greater than its magnitude. When dealing with highschool phyics problems, the magnitude is usually the sum of two or more components and one component will offset the other, causing the magnitude to be less then its component
-- Distance is a scalar quantity, whereas displacement is a vector. -- Distance is the integral of magnitude of displacement. -- Magnitude of displacement is always less than or equal to distance. -- The two quantities are equal when the motion is in a straight line.
No. The magnitude of a vector can't be less than any component.
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(Magnitude of the vector)2 = sum of the squares of the component magnituides Let's say the components are 'A' and 'B', and the magnitude of the vector is 'C'. Then C2 = A2 + B2 You have said that C = A, so C2 = C2 + B2 B2 = 0 B = 0 The other component is zero.
The magnitude of the sum of any two vectors can be anywhere between zero and the sum of their two magnitudes, depending on their magnitudes and the angle between them. When you say "components", you're simply describing a sum of two vectors that happen to be perpendicular to each other. In that case, the magnitude of their sum is Square root of [ (magnitude of one component)2 + (magnitude of the other component)2 ] It looks to me like that can't be less than the the magnitude of the greater component.
No. The magnitude of a vector can't be less than any component.
scalar, produced by the scalar product of two vector quantities ... Force · Distance
Well, a scalar is simply a quantity with no direction (as contrasted to a vector, which has direction). So, I suppose, one might say: a direction-less number?