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Are two squares with the same perimeter congruent?
Yes, if the perimeters are the same, then both of them have side = perimeter / 4. And of course the angles are all 90°, since they are squares.
What is the perimeter of a rhombus with side length of 30 in and 40 in?
A rhombus can't have two different side lengths. They all must be the same. If the sides are 30-in, then the perimeter is 120-in. If they're 40-in, then the perimeter is 160-in.
What is the length of a squares side if the perimeter in 272 mm?
Each side of the square is 272/4 = 68 mm
Why can you have a shape with different perimeters but the same area?
they are different because perimeter is the out side of the shape and area is inside of the shape.
Can a square have the same perimeter and area?
The area and perimeter might be written with the same number,but they can't be 'the same' because they have different units.If the length of the side of the square is 4 feet, thenits perimeter is 16 feet and its area is 16 square feet.These are not 'the same'.
What is the perimeter of a square if it has a area of 81 centimetre squares?
Area of square = 81 cm2 so side of square = 9 cm and then perimeter = 4*side = 36 cm.
What is the length of the longest side the perimeter of the triangle is 63 in.?
The perimeter doesn't tell you the length of any of the sides. There are an infinite number of different triangles that all have the same perimeter. The only thing you can tell from a 63-in perimeter is that no side can be 31.5 inches or more.
How big are three identical squares if when placed side by side they have a perimeter of 120 inches?
15 x 15 inches.
If two squares have the same side lengths are the two squares necessarily congruent?
If two squares have the same side length for all sides, then they are congruent.
What are two different size squares that the ratio of their perimeters is the same as the ratio of their areas?
Assume square A with side a; square B with side b. Perimeter of A is 4a; area of A is a2. Perimeter of B is 4b; area of B is b2. Given the ratio of the perimeters equals the ratio of the areas, then 4a/4b = a2/b2; a/b = a2/b2 By cross-multiplication we get: ab2 = a2b Dividing both sides by ab we get: b = a This tells us that squares whose ratio of their perimeters equals the ratio of their areas have equal-length sides. (Side a of Square A = side b of Square B.) This appears to show, if not prove, that there are not two different-size squares meeting the condition.
What is the ratio of the length of the side of a square to it's perimeter?
its 1:4. Perimeter = sum of length of all sides. squares have 4 equal sides.
Can you find the area of a rectangle only knowing the perimeter?
To find the area of a rectangle, you multiply the length by the width (one side by a different side) Or you could count how many centimeter squares make up the rectangle
