In normal math, 1 is not equal to 0, so any "proof" that they are equal either uses non-standard definitions, or it is based on faulty logic.
(a to the power of 1)/(a to the power of 1)=1 So, a to the power of (1-1)=1 Therefore, a to the power of 0=1
You can't it equals 2. You can't it equals 2.
a0=(a-1\a-1)=a\a=1
2sinx+1 equals 0
Everything to the power of 0 equals 1.
Secant is 1 over cosine and cosine 0 equals 1.
You cannot prove that sqrt(3)/2 = 0 because it is simply not true! The solution to the equation is theta (or, tita as you like to call it) = pi/6c or 30 degrees. The cosine of that angle is sqrt(3)/2 but that is NOT the same as it being 0.
Using faulty logic.
Using a calculator
Yes because if 1+0=1 than 0 plus b equals b
If it's 1 +-1 =0
no - 10 doesn't equal 1However, could consider the so-called 'Bold Hypothesis' (introducing a new mathematical object (infinity) which equals 1/0, but otherwise behaves like a real number):1/0=infinity, therefore 1=infinity*0you know: 10*0=1*0 (any number *0=0)multiply each side by infinity (1/0): 10*0*infinity=1*0*infinitywhich is the same as: 10*(0*infinity)=1*(0*infinity)we have already said (1st line) that 1=infinity*0, therefore: 10*1=1*1which simplifies to give: 10=1which is impossible?!