2sinx+1 equals 0
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cos2x + 2sinx - 2 = 0 (1-2sin2x)+2sinx-2=0 -(2sin2x-2sinx+1)=0 -2sinx(sinx+1)=0 -2sinx=0 , sinx+1=0 sinx=0 , sinx=1 x= 0(pi) , pi/2 , pi
4 sin2x = 1. Then, (2sinx)2 = 1, 2sinx = ±1, and sinx = ±½. Whence, x = 90° or 270°; or, in radians, x = π/2 or 3π/2.
x2+1/4x = 0 x(x+1/4) = 0 Therefore: x = 0 or x = -1/4
X = 0 (zero) Y = -1 (neg 1)
(4 ± i2) where i2 = -1