Yes, if you take the range to be inclusive, it even works for 1, since 2 is prime.
The theorem related to this question is called Bertrand's Postulate, or Chebyshev's Theorem, or the Bertrand-Chebyshev theorem.
Take any counting number greater than one. 2, 3, 4, 5 and so on. Double it. Between the number and twice the number, there will be at least one prime number. 3, a prime number, is in between 2 and 4.
Yes.
No, the sum of a prime number and a composite number is not always even.
It is 97. it is largest, because it is the largest double digit prime number.
No, not always. When you reverse a two-digit prime number, the result may or may not be a prime number. It depends on the specific number you are reversing.
Take any counting number greater than one. 2, 3, 4, 5 and so on. Double it. Between the number and twice the number, there will be at least one prime number. 3, a prime number, is in between 2 and 4.
odd is a number you cant halve a prime number is a number that you can double itself and it is odd
"Double prime" is a term used in calculus. I have found no information on anything called a "double prime number".
Yes.
No, the sum of a prime number and a composite number is not always even.
It is 97. it is largest, because it is the largest double digit prime number.
No, reversing the order of the digits of a two-digit prime number does not always result in a prime number.
"Double prime" is a term used in calculus. I have found no information on anything called a "double Prime number".
No, not always. When you reverse a two-digit prime number, the result may or may not be a prime number. It depends on the specific number you are reversing.
It is always 1 and the prime number itself.
Yes, a prime number is always greater than 1.
Never. 1 is not a prime number.