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How many times does the prime factor 2 appear in the factorization of 130?
You can find the prime factorization of 130: 130 = 2*5*13 Therefore the answer is 1. Or you can skip a step. Just divide 130 by 2. You get 65, which is an odd number. Therefore there is only 1 factor of 2 in the factorization of 130.
Find the prime factorization of the number130?
130 = 2 x 5 x 13
What is the prime factorrization of 130?
The prime factorization of 130 is 2x5x13.
What is the prime factorization using exponents of 130?
Prime factorization of 130 is 2x5x13, (or 21x51x131 if unnecessary exponents must be shown).
What is a prime factorization for 130?
The prime factorization is: 2 x 5 x 13
What is tbe prime factorization of 130?
2 x 5 x 13 = 130
What is the prime factorization of 130 using a factor tree?
2*5*13 = 130
What is the Prime Factorization of 130?
Prime factorization of 130 is: 2 x 5 x 13. 2 x 5 x 13 = 130 2 x 5 x 132 x 5 x 13 = 130
Prime factorization of 130 using exponents?
It is: 2*5*13 = 130 and exponents are not needed
How many times does the prime factor 2 appear in 130?
You can just divide 130 by 2 and get 65, which is odd so it doesn't have 2 as a factor. Therefore the answer is 1.Answer 1You need to find the prime factorization of 130. 130 = 2*5*13Therefore the answer is 1.
What is a prime factorizaton for the number 130?
The prime factorization of 130 is 2 x 5 x 13.
What are all the numbers that go into 130 talking about prime factorization?
2 x 5 x 13 = 130
