Yes. 25x4=100 or 143-43=100
100+0=100
#include <iostream> using namespace std; int main() { cout << "Even from 0-100: \n\n"; for(int i = 0; i <= 100; i++) { if(i % 2 == 0 && i != 0) { cout << i << endl; } } cout << "Odd from 0-100: \n\n"; for(int i = 0; i < 100; i++) { if(i % 2 != 0) { cout << i << endl; } } char wait; cin >> wait; return 0; }
No.
75 - 100 + 0 = -25
I dont know my stupid teacher wont tell me old hack
1x+4y=
If: y = x2+20x+100 and x2-20x+100 Then: x2+20x+100 = x2-20x+100 So: 40x = 0 => x = 0 When x = 0 then y = 100 Therefore point of intersection: (0, 100)
#include <iostream> using namespace std; int main() { for(int i = 0; i <= 100; i++) { if(i % 2 != 0) { cout << i << endl; } } char wait; cin >> wait; return 0; }
The answer is 24. Simply add up all of the numbers arithmetically like you would for two plus two. To make sure the answer is correct, check your work using a calculator.
#include using std::cout;using std::endl;int main(){int sum = 0;cout
-987 + 654 + 321 = 0 .
-100(negative 100)+100(positive 100)=0. If you have 100 of something(the +100) and then take away 100 (the -100), you're left with nothing (the 0). So it's 0.