If: y = x2+20x+100 and x2-20x+100
Then: x2+20x+100 = x2-20x+100
So: 40x = 0 => x = 0
When x = 0 then y = 100
Therefore point of intersection: (0, 100)
They intersect at the point of: (-3/2, 11/4)
1,6
The intersection is (-2, 6)
It works out that the point of intersection is at (-4, -3.5) on the Cartesian plane.
2
The coordinates of the point of intersection is (1,1).
3
The point of intersection of the given simultaneous equations of y = 4x-1 and 3y-8x+2 = 0 is at (0.25, 0) solved by means of elimination and substitution.
When x = -2 then y = 4 which is the common point of intersection of the two equations.
Probably not. But there is not enough information in the question to be certain.
hyperbolas have an eccentricity (fixed point to fixed line ratio) that is greater than 1, while the parabolas have an exact eccentricity that is equal to 1. And hyperbolas are always come in pairs while parabolas are not.
The point of intersection.