Any order which ends in 2, 4 or 6 will do.
If the number is even, it is a multiple of 2 If the sum of the digits make a number divisible by 3, the number is a multiple of 3 If the number ends in 5 or 0, the number is a multiple of 5 If the number is divisible by 2 and 3, the number is a multiple of 6 If the sum of the digits make a number divisible by 9, the number is a multiple of 9
Just one. In combinatorials, the order of the digits in a combination does not make a difference.Just one. In combinatorials, the order of the digits in a combination does not make a difference.Just one. In combinatorials, the order of the digits in a combination does not make a difference.Just one. In combinatorials, the order of the digits in a combination does not make a difference.
342 is divisible by 6 and not 5.Numbers divisible by 5 end in zeros or fivesNumbers divisible by 6 have a slightly more complicated rule. If, when the individual digits are added together and they make a multiple of 3, see if the number is even. If so, and the digits add up to a multiple of 3, then the number is a divisible by 6.
A prime number is only divisible by 1 and itself. If all three digits have to be used then any number formed from them is divisible by 9 as the sum of the digits = 9. Thus no prime number can be formed. If only two of the three digits are used then it cannot end in 0 or 8 as it would be divisible by 2. This only leaves 81 where the digits again total 9 and thus is divisible by 9. None of the single digits 0,1,8 are prime. 8 is an even number. 1 is classed as unity, 0 is zero.
You can always tell a number is divisible by eight by checking to see if the rightmost three digits are. If they are, then the whole number is. With that in mind then, you can make up all sorts of such numbers by just grabbing some combination that you know is divisible by eight, and tacking additional digits on to the left. For example, we know that 128 is divisible by eight (128 / 8 = 16), so any of these numbers are as well: 89469128 13948128 90173128 The number of digits doesn't matter, so we also know that a ridiculously large number like this one: 25098174509840582437575109283102477568758134024 is divisible by eight, because the last three digits are.
Any number divisible by 3 has digits that add up to a multiple of 3. Adding a 1 to any of these digits or inserting a 1 anywhere in the number would make it divisible by 3.
123456
132456
If the number is even, it is a multiple of 2 If the sum of the digits make a number divisible by 3, the number is a multiple of 3 If the number ends in 5 or 0, the number is a multiple of 5 If the number is divisible by 2 and 3, the number is a multiple of 6 If the sum of the digits make a number divisible by 9, the number is a multiple of 9
The 5 should be deleted.
Just one. In combinatorials, the order of the digits in a combination does not make a difference.Just one. In combinatorials, the order of the digits in a combination does not make a difference.Just one. In combinatorials, the order of the digits in a combination does not make a difference.Just one. In combinatorials, the order of the digits in a combination does not make a difference.
342 is divisible by 6 and not 5.Numbers divisible by 5 end in zeros or fivesNumbers divisible by 6 have a slightly more complicated rule. If, when the individual digits are added together and they make a multiple of 3, see if the number is even. If so, and the digits add up to a multiple of 3, then the number is a divisible by 6.
A number is divisible by 8 if and only if it is an integer and the last three digits make a number that is divisible by 8. A general divisibility rule for 2^n where n is an integer is to take the last n digits and if they make a number that is divisible by n then it is divisible by n.
A prime number is only divisible by 1 and itself. If all three digits have to be used then any number formed from them is divisible by 9 as the sum of the digits = 9. Thus no prime number can be formed. If only two of the three digits are used then it cannot end in 0 or 8 as it would be divisible by 2. This only leaves 81 where the digits again total 9 and thus is divisible by 9. None of the single digits 0,1,8 are prime. 8 is an even number. 1 is classed as unity, 0 is zero.
I don't completely understand the question, but there's a trick: A number is divisible by 3 if and only if the sum of its digits is divisible by 3. This should guide you to an answer.
descending order
the rule for divisibility by 9 is that the sum of all digits of the number should should be divisible by 9. So, 3+9+0+6+5= 23. To make is divisible by 9, we think of 27 (as the next number divisible by 9) and that means if we add 4 to any digit of the number, it will be divisible. 39069/9=4341