10056÷23 gives 437 as quotient and 5 as remainder. Dividend-remainder= divisor× quotient so 10056-5=23×437 gives 10051.our question is least no should be added to 10056 which is divisible by 23. Check next possibility 23×438 gives 10074. Now 10056+18= 10074. Therefore 18 is the least number should be added to 10056 to get a number divisible by 23
It is: 36 and so 960/48 = 20
To find the least number that should be added to 3500 to make it divisible by 42, 49, 56, and 63, we need to find the least common multiple (LCM) of these four numbers. The LCM of 42, 49, 56, and 63 is 1764. To make 3500 divisible by 1764, we need to find the remainder when 3500 is divided by 1764, which is 1972. Therefore, the least number that should be added to 3500 to make it divisible by 42, 49, 56, and 63 is 1764 - 1972 = 208.
339 + 1 = 340,which is exactly divisible.
8 added to 4952 makes it divisible by 32
10056÷23 gives 437 as quotient and 5 as remainder. Dividend-remainder= divisor× quotient so 10056-5=23×437 gives 10051.our question is least no should be added to 10056 which is divisible by 23. Check next possibility 23×438 gives 10074. Now 10056+18= 10074. Therefore 18 is the least number should be added to 10056 to get a number divisible by 23
It is: 36 and so 960/48 = 20
Any number ending in 3.
Nope - 1038 is an even number and thus is divisible by 2. Its digits added together total 12 - which is divisible by 3... therefore the original number is also divisible by 3 !!
To find the least number that should be added to 3500 to make it divisible by 42, 49, 56, and 63, we need to find the least common multiple (LCM) of these four numbers. The LCM of 42, 49, 56, and 63 is 1764. To make 3500 divisible by 1764, we need to find the remainder when 3500 is divided by 1764, which is 1972. Therefore, the least number that should be added to 3500 to make it divisible by 42, 49, 56, and 63 is 1764 - 1972 = 208.
339 + 1 = 340,which is exactly divisible.
8 added to 4952 makes it divisible by 32
Nope - For any number to be divisible by three, the sum of the digits added together must ALSO be divisible by three. In this case 1+4=5.
9 ============================== Another contributor added more answers: Multiply 9 by any whole number. The answer is divisible by 3 and 9. There are an infinite number if them.
5715 is not divisible by 2: the last digit is not an even number or 05715 is divisible by 3: as the last two digits when added together is a multiple of 35715 is divisible by 5: as the last digit is a 5 or 05715 is divisible by 9: as if u added all the digits of the number it will be divisible by 9, in this case 5 +7+1+5=18 and 18 is a multiple of 95715 is not divisible by 10: as the last digit is not a 0
Answer: 2A number is divisible by 3 if the sum of its digits is a multiple of 3.Now 2+1+4=7. If we add 2 more it is 9 which is a multiple of 3.So 216 is divisible by 3 since 2+1+6=9 which is a multiple of 3.
5, 7, a bunch of numbers that are odd are not divisible by 3. numbers that are divisible by three can have all their numbers added together and come out with a number that is divisible by 3.