y = 2x + 1.
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
A quadratic equation.
A transform boundary can form earthquakes and transform faults.
what is the slope-intercept form of the equation 15y=10x+12
Solving the equation for "y" gives you the slope-intercept form.
It is the general form of a quadratic equation.
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
It actually means "reacts to form".
x = 4.5
It depends on the rest of the equation and the form it takes.
No, not if the y is squared. When graphed the equation will not form a straight line.
The equation contains variables which are only raised to the first power.
There are no "following" data!
x + y = 3
transform boundaries form at mid-ocean ridges!
It is a straight line equation that can be simplified to: y = 3x-9
It is slope intercept form. The equation for slope intercept form is y=mx+b which is like your equation y=5x+6
A linear equation in the slope intercept form or the standard form.
It is an expression in two variable: it is NOT an equation. There is no standard form for expressions.
You also need an equation for y in order to convert to rectangular form.
It is: y = 0.25x-0.875 in slope intercept form
It depends on what you are calling "standard form". 2x = 7 can be solved, but it is a standard form of an algebraic equation.