y=mx+b
y0=mx0+b
5=3*2+b
b=5-5=0
y=3x+0
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The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
It is: y-7 = 2(x-3) => y = 2x+1
As a straight line equation: y = -3x+18 in slope intercept form
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
If you mean a slope of 23 and a point of (0, 4) then the equation is y = 23x+4
y = 2x + 1.
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
The answe iss..... 6
y = 2x - 1
y=2x+1
It is: y = 2x-6
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
It is: y-7 = 2(x-3) => y = 2x+1
As a straight line equation: y = -3x+18 in slope intercept form
Choose the equation of the line that contains the points (1, -1) and (2, -2).