Best Answer

The equation of the line is of the form y = 3x + c where c is a constant.

The point (4,9) is on the line, so substituting x=4, y=9 in the equation,

9 = 3*4 + c = 12 + c so c = -3

So the equation of the line is y = 3x - 3

Q: Write the equation in slopeintercept form of the line that has a slope of 3 and contains the point 4 9?

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y = 2x - 1

It is: y = 2x-6

if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form

Slope: -5 Points: (6, 3) Equation: y = -5x+33

If you mean a slope of 2/5 and the point (-15, 12) then equation is 5y = 2x+90

Related questions

y = 2x + 1.

y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0

Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).

y = 2x - 1

y=2x+1

The answe iss..... 6

It is: y = 2x-6

The equation is (y - 1) = 2(x - 1) or, y = 2x - 1

if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form

Choose the equation of the line that contains the points (1, -1) and (2, -2).

It is: y-7 = 2(x-3) => y = 2x+1

As a straight line equation: y = -3x+18 in slope intercept form