Arc_length = angle_in_radians x radius
= π/6 x 24cm
= 4π cm
the radius
It is certainly possible. All you need is a the second circle to have a radius which is less than 20% of the radius of the first.
If the central angle is 70 and the radius is 8cm, how do you find out the chord lenght?
The length of an arc of a circle is the radius times the angle (in radians). So a full circle is an angle of 2*pi radians, and the circumference of a circle is 2*pi*radius. A half circle is pi*radius. Quarter circle is (pi/2)*radius, etc.
You can think of an arc as a fraction of the circumferance of a circle. Also, a complete circle is 2pi radians, so any central angle is THETA / 2pi of a complete circle. Multiply by the circumferance to get the length of the arc: THETA / 2pi * 2(pi)(r) = THETA * r or the length of the arc is simply the radius times the central angle in radians
The length of an arc of a circle refers to the product of the central angle and the radius of the circle.
If the radius of a circle is tripled, how is the length of the arc intercepted by a fixed central angle changed?
(arc length / (radius * 2 * pi)) * 360 = angle
-- Circumference of the circle = (pi) x (radius) -- length of the intercepted arc/circumference = degree measure of the central angle/360 degrees
Radius: A line from the center of a circle to a point on the circle. Central Angle: The angle subtended at the center of a circle by two given points on the circle.
the radius
Length of arc = angle (in radians)*radius = (pi/4)*14 = 10.996 cm
Central angle of a circle is the same as the measure of the intercepted arc. davids1: more importantly the formulae for a central angle is π=pi, R=radius Central Angle= Arc Length x 180 / π x R
5.23
It is certainly possible. All you need is a the second circle to have a radius which is less than 20% of the radius of the first.
If this is a central angle, the 72/360 x (2xpix4) = 5.024
If the sector of a circle has a central angle of 50 and an area of 605 cm2, the radius is: 37.24 cm